Question

我想要在单个查询中列出Odd和Even的数字，我只是发现奇数或偶数之一，下面是我的代码

SELECT * FROM 
 ( SELECT T.C_DATE,T.C_NAME,T.C_TIME,L_UID, ROWNUM RANK 
     FROM TENTER T)
    WHERE MOD(RANK,2)=1
      AND C_DATE BETWEEN :P_FROM_DATE AND :P_TO_DATE 
    ORDER BY L_UID, C_TIME ASC;

Answer 1

您应该能够在没有子查询的情况下执行此操作。假设您只希望每行有一个标签：

SELECT T.C_DATE, T.C_NAME, T.C_TIME, L_UID, ROWNUM as RANK,
       (CASE WHEN MOD(ROWNUM, 2) = 0 THEN 'EVEN' ELSE 'ODD' END) as even_odd_label 
FROM TENTER T
WHERE C_DATE BETWEEN :P_FROM_DATE AND :P_TO_DATE 
ORDER BY L_UID, C_TIME ASC;

Answer 2

您可以使用：

SELECT decode(mod(TT.RANK,2),0,'Even','Odd') as rank,
       TT.*
  FROM 
 ( SELECT T.C_DATE,T.C_NAME,T.C_TIME,L_UID, 
          ROW_NUMBER() OVER (ORDER BY L_UID, C_TIME ASC) as RANK 
     FROM TENTER T) TT
    WHERE C_DATE BETWEEN :P_FROM_DATE AND :P_TO_DATE
    ORDER BY L_UID, C_TIME ASC;

P.S。顺便说一句，我建议您使用带有特定序号的ROW_NUMBER函数，而不是系统生成的ROWNUM伪列。

单个Oracle SQL查询中的奇偶数

2 个答案: