Question

我需要一个SQL查询/函数，它会找出数字的SUM，它出现在偶数位置，数字的SUM存在于奇数位置。

示例：

如果数字为440065385：

x=4+0+6+3+5=18(x is holding sum of odd positions)
y=4+0+5+8=17 (y holds the sum of even positions).

感谢。

Answer 1

您可以使用数字表连接您的表格，将所有数字拆分成行，然后将赔率甚至位置数字分开。

with positions(position) as 
    (select level from dual connect by level <=25
    ),
digits as
    (
    select 
        t1.v,
        n.position ,
        cast(substr(t1.v ,length(t1.v) - n.position + 1, 1) as int) as digit
    from my_table t1 left join positions n
    on n.position <= length(t1.v)
    )
select
    v,
    sum(case when mod(position,2)=0 then digit else 0 end) as evensum,
    sum(case when mod(position,2)=1 then digit else 0 end) as oddsum
from
    digits
group by
    v

测试Sql Fiddle，结果：

V           EVENSUM ODDSUM
440065385   17      18

Answer 2

您可以使用级别模拟迭代，并通过连接来实现相同的

with iterate as 
(select level as i from dual connect by level <=25)
 select
       table1.column1, 
       sum(decode(mod(iterate.i,2),0,substr(table1.column1,iterate.i,1))) sum_even,
       sum(decode(mod(iterate.i,2),1,substr(table1.column1,iterate.i,1))) sum_old
 from table1 ,iterate 
 where iterate.i <=length(table1.column1)
 group by table1.column1

sql查询计算奇数和偶数位数总和

2 个答案: