您好,我正在尝试运行一个程序,该程序将返回学生的成绩及其平均成绩。我还知道我是基本的第一年程序员。我可能会很担心。无论如何,请最好的帮助。 谢谢。
错误说是在第49行。
说“
line 49, in <module>
while ids > STOP:
TypeErrorL unorderable types: str() > int()
XXXX
def assigngrades(scores):
avg = sum(scores)/len(scores)
print(avg)
for val in scores:
if val > avg + 10:
grade = 'A'
elif val > avg + 5:
grade = 'B'
elif val > avg -5:
grade = 'C'
elif val > avg - 10:
grade = 'D'
else:
grade = 'F'
grades.append(grade)
print("in assigngrades, grades: ",grades)
return grades
def printsummary(grades, ave):
print('ID Score Average Grade')
print('===========================================')
print( )
for val in range(len(ids)):
print('val', val)
print(ids,' ',scores, ' ', grades)
return
#main
ids = []
scores = []
grades = []
STOP = 0
ids = input("Enter an ID:")
while ids > STOP:
ids.append(ids)
score = eval(input("Enter a score:"))
scores.append(score)
id = (input("Enter an ID number, 0 to STOP:"))
grades = assigngrades(scores)
print("after while loop")
print("Ids:", ids, "Scores:", scores, "Grades:", grades)
printsummary(grades, avg)
尽管如此,我对这个问题感到困惑。感谢您的宝贵时间,并帮助您解决此问题。非常感谢。是的,我知道我很傻。
答案 0 :(得分:1)
input()
函数返回一个字符串,因此应使用int()
将其转换为整数,以便可以将其值与另一个整数进行比较。您还应该命名存储用户输入的变量,而不是ids
,因为您已经将其定义为列表:
ids = []
scores = []
grades = []
STOP = 0
id = int(input("Enter an ID:"))
while id > STOP:
ids.append(id)
score = eval(input("Enter a score:"))
scores.append(score)
grades = assigngrades(scores)
print("after while loop")
print("Ids:", ids, "Scores:", scores, "Grades:", grades)
printsummary(grades, avg)