Question

你们可以帮我找到错误的代码部分吗？我尝试了一些东西并在这个网站上搜索，但我找不到解决方案..如果你们知道的话，请告诉我们：D

print("Uw formule is ax**2+bx+c")
a= float(input("Geef getal a:" ))
b= float(input("Geef getal b:" ))         
c= float(input("Geef getal c:" ))
D=b**2-4*a*c

while (D<=0) or (a==0):
    print("Voer nieuwe getallen in, de uitkomst is niet te berekenen")
    a= float(input("Geef getal a:" ))
    b= float(input("Geef getal b:" ))
    c= float(input("Geef getal c:" ))
    D=b*b-4*a*c
    D= format(D,'.1f')

if (D>0):
    print("\nDe discriminant is:", D )
    x1= (-b-(D)**0.5)/(2*a)
    x1= format(x1,'.1f')
    x2= (-b+(D)**0.5)/(2*a)
    x2= format(x2,'.1f')

print("De uitkomst van x1=", x1)
print("De uitkomst van x2=", x2)

然后是错误：

Traceback (most recent call last):
  File "*****", line 15, in <module>
    while (D<=0) or (a==0):
TypeError: unorderable types: str() <= int()

Answer 1

在for循环结束时，您将D重新分配给调用format的结果。这将永远使它成为一个字符串。

我不确定你为什么这样做，但你应该删除该行。

Answer 2

谢谢！我解决了它：

print("Uw formule is ax**2+bx+c")
a= float(input("Geef getal a:" ))
b= float(input("Geef getal b:" ))         
c= float(input("Geef getal c:" ))
D=b**2-4*a*c

while (D<=0) or (a==0):
    print("Voer nieuwe getallen in, de uitkomst is niet te berekenen")
    a= float(input("Geef getal a:" ))
    b= float(input("Geef getal b:" ))
    c= float(input("Geef getal c:" ))
    D=b*b-4*a*c
    D1= format(D,'.1f')  #this code

if (D>0):
    print("\nDe discriminant is:", D1 )
    x1= (-b-(D)**0.5)/(2*a)
    x1= format(x1,'.1f')
    x2= (-b+(D)**0.5)/(2*a)
    x2= format(x2,'.1f')

print("De uitkomst van x1=", x1)
print("De uitkomst van x2=", x2)

TypeError：unorderable类型：str（）＆lt; = int（）错误

2 个答案: