Question

我知道这听起来可能很奇怪，但是我需要制作一个记忆游戏，将不同的图像而不是两个相同的图像进行匹配，例如，一个数字和一只食指抬起的手

这是我的实际代码，可匹配两个相同的图像，它克隆了使相同图像出现两次的卡片

下面的场景控制器

using System.Collections;
using System.Collections.Generic;
using UnityEngine;
using UnityEngine.SceneManagement;

public class SceneController : MonoBehaviour {

public const int gridRows = 2;
public const int gridCols = 5;
public const float offsetX = 4f;
public const float offsetY = 5f;

[SerializeField] private MainCard originalCard;
[SerializeField] private Sprite[] images;

private void Start()
{
    Vector3 startPos = originalCard.transform.position; //The first position of the cards, all other cards are based on this one

    int[] numbers = { 0, 0, 1, 1, 2, 2, 3, 3, 4, 4};
    numbers = ShuffleArray(numbers); 

    for(int i = 0; i < gridCols; i++)
    {
        for(int j = 0; j < gridRows; j++)
        {
            MainCard card;
            if(i == 0 && j == 0)
            {
                card = originalCard;
            }
            else
            {
                card = Instantiate(originalCard) as MainCard;
            }

            int index = j * gridCols + i;
            int id = numbers[index];
            card.ChangeSprite(id, images[id]);

            float posX = (offsetX * i) + startPos.x;
            float posY = (offsetY * j) + startPos.y;
            card.transform.position = new Vector3(posX, posY, startPos.z);
        }
    }
}

private int[] ShuffleArray(int[] numbers)
{
    int[] newArray = numbers.Clone() as int[];
    for(int i = 0; i < newArray.Length; i++)
    {
        int tmp = newArray[i];
        int r = Random.Range(i, newArray.Length);
        newArray[i] = newArray[r];
        newArray[r] = tmp;
    }
    return newArray;
}

//-------------------------------------------------------------------------------------------------------------------------------------------

private MainCard _firstRevealed;
private MainCard _secondRevealed;

private int _match = 5;
[SerializeField] private TextMesh matchLabel;

public bool canReveal
{
    get { return _secondRevealed == null; }
}

public void CardRevealed(MainCard card)
{
    if(_firstRevealed == null)
    {
        _firstRevealed = card;
    }
    else
    {
        _secondRevealed = card;
        StartCoroutine(CheckMatch());
    }
}

private IEnumerator CheckMatch()
{
    if(_firstRevealed.id == _secondRevealed.id)
    {
        _match--;
        matchLabel.text = "Pares Restantes: " + _match;
        if(_match == 1){
            matchLabel.text = "Somente " + _match + " Par Restante";
        }
        if(_match == 0){
            SceneManager.LoadScene("Sucesso");
        }
    }
    else
    {
        yield return new WaitForSeconds(0.5f);

        _firstRevealed.Unreveal();
        _secondRevealed.Unreveal();
    }

    _firstRevealed = null;
    _secondRevealed = null;

}

public void Menu()
{
    SceneManager.LoadScene("Menu");
}

public void Fases()
{
    SceneManager.LoadScene("Fases");
}

public void Sair()
{
    Application.Quit ();
}

public void Level1()
{
    SceneManager.LoadScene("Level 1");
}

public void Sucesso()
{
    SceneManager.LoadScene("Sucesso");
}

}

下面的主卡类别

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class MainCard : MonoBehaviour {

[SerializeField] private SceneController controller;
[SerializeField] private GameObject Card_Back;


public void OnMouseDown()
{
    if(Card_Back.activeSelf && controller.canReveal)
    {
        Card_Back.SetActive(false);
        controller.CardRevealed(this);
    }
}


private int _id;
public int id
{
    get { return _id; }
}

public void ChangeSprite(int id, Sprite image)
{
    _id = id;
    GetComponent<SpriteRenderer>().sprite = image; //Isso pega o Sprite Renderer e muda a propriedade do Sprite
}

public void Unreveal()
{
    Card_Back.SetActive(true);
}

}

PS：对不起，我的英语

Answer 1

您可以像以下简单示例一样将每个图像封装在类的对象中：

class CardImage : MonoBehaviour
{
    public Sprite cardSprite;
    public int cardNumber;
}

然后在您的游戏逻辑中，您可以检查cardNumber字段，以比较两张卡片，如下所示：

if (card1.cardNumber == card2.cardNumber)
{
// Do what you have to do when two cards are equal
}

有关OOP和封装的更多信息，请参见this

记忆游戏-如何与其他图片匹配？

1 个答案: