Question

如何不跳过年份数组的元素？

我希望结果是：

<com.like.LikeButton
    app:icon_type="heart"
    app:icon_size="25dp"
    android:id="@+id/heart_button"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"/>

当前结果：

Banana
0
Mango
1

此处的代码：

Banana
0
Mango
3

Answer 1

像您一样遍历数组，并在水果与case语句之一匹配时增加第二个计数器。使用计数器从数组中获取年份数字：

var fruits, text, year, i;
fruits = ["Banana", "Orange", "Apple", "Mango"];
year = ["0", "1", "2", "3"];
text = "<ul>";
let counter = 0; // <-- define a second counter
for (i = 0; i < fruits.length; i++) {
  switch (fruits[i]) {
    case 'Mango':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++; // <-- that only get's incremented when a case is matched
      break;
    case 'Pine apple':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++;
      break;
    case 'Grape':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++;
      break;
    case 'Banana':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++;
      break;
  }
}
text += "</ul>";
document.getElementById("demo").innerHTML = text;

<p id="demo"></p>

如何避免在第二个数组中跳过数组索引？

1 个答案: