我正在编写一个程序，将任何输入金额转换为二十，十，五和一的面额。这是我遇到的麻烦：
.attrEntry .error.itemLevel,
.attrEntry .helpText,
.attrEntry .tiny {
display: none!important;
}
.attrEntry .error.itemLevel.show {
display: block!important;
}
美元是输入金额，二十年代的表达方式似乎是唯一可以正确表达的方式。例如：我输入161，结果是161等于8二十，4十，2个5和0。但是应该出来，因为161等于8二十，0十，0五和一。我知道有一个非常简单的答案，谢谢大家。
答案 0 :(得分：2)
您必须使用余数并减去，直到余数变为0；
int amount = 161, temp = 0;
int[] denomination = { 20, 10, 5, 1 }; // you can use enums also for
// readbility
int[] count = new int[denomination.Length];
while (amount > 0)
{
count[temp] = amount / denomination[temp];
amount -= count[temp] * denomination[temp];
temp ++;
}
答案 1 :(得分：1)
删除这些面额后，您需要处理其余部分。最简单的方法是modulus operator，就像这样……
int dollar = 161;
int twenties = dollar / 20;
int remainder = dollar % 20;
int tens = remainder / 10;
remainder = remainder % 10;
int fives = remainder / 5;
remainder = remainder % 5;
int ones = remainder;
上述方法不会修改原始金额。通过将其重构为一种方法，可以更轻松地以不同面额重复使用：
public int RemoveDenomination(int denomination, ref int amount)
{
int howMany = amount / denomination;
amount = amount % denomination;
return howMany;
}
...您可以这样使用...
int dollar = 161;
int hundreds = RemoveDenomination(100, ref dollar);
int fifties = RemoveDenomination(50, ref dollar);
int twenties = RemoveDenomination(20, ref dollar);
int tens = RemoveDenomination(10, ref dollar);
int fives = RemoveDenomination(5, ref dollar);
int ones = dollar;
此方法确实修改了dollar的值。因此，如果您不想更改它，请在另一个变量中创建一个副本，然后在副本上进行操作。
答案 2 :(得分：1)
另一种选择是使用linq：
int[] denominations = new [] { 20, 10, 5, 1 };
List<int> result =
denominations
.Aggregate(new { Result = new List<int>(), Remainder = 161 }, (a, x) =>
{
a.Result.Add(a.Remainder / x);
return new { a.Result, Remainder = a.Remainder % x };
})
.Result;
这将返回一个带有值{ 8, 0, 0, 1 }的列表。
或者，您可以执行以下操作：
public static Dictionary<string, int> Denominations(int amount)
{
var denominations = new Dictionary<string, int>();
denominations["twenties"] = amount / 20;
amount = amount % 20;
denominations["tens"] = amount / 10;
amount = amount % 10;
denominations["fives"] = amount / 5;
amount = amount % 5;
denominations["ones"] = amount;
return denominations;
}
答案 3 :(得分：0)
此控制台应用说明了可能的解决方案：
internal static class Program
{
internal static void Main()
{
var results = GetDenominationValues();
foreach (var result in results)
{
Console.WriteLine($"{result.Key} - {result.Value}");
}
Console.ReadLine();
}
private static Dictionary<int, int> GetDenominationValues()
{
var amount = 161;
var denominations = new[] { 20, 10, 5, 1 };
var results = new Dictionary<int, int>();
foreach (var denomination in denominations)
{
results.Add(denomination, amount / denomination);
amount = amount % denomination;
if (amount == 0) break;
}
return results;
}
}
关键区别在于：
amount = amount % denomination;
在随后的计算中使用前一个除法的余数。
答案 4 :(得分：-1)
如果除法大于零，则将余数传递（使用模运算符%），否则将原始值传递给行中的下一个除法。重复直到没有更多的划分。
另外，将tens除以10，fives除以5，将ones除以1。
答案 5 :(得分：-2)
请使用下面的返回字典的函数
public static Dictionary<string, int> Denominations(int amount)
{
Dictionary<string, int> denominations = new Dictionary<string, int>() { { "twenties", 0 }, { "tens", 0 }, { "fives", 0 }, { "ones", 0 } };
int twenties, tens, fives, ones;
if (amount >= 20)
{
twenties = amount/20;
denominations["twenties"] = twenties;
amount -= twenties * 20;
}
if (amount >= 10)
{
tens = amount/10;
denominations["tens"] = tens;
amount -= tens * 10;
}
if (amount >= 5)
{
fives = amount/5;
denominations["fives"] = fives;
amount -= fives * 5;
}
if (amount >= 1)
{
ones = amount;
denominations["ones"] = ones;
}
return denominations;
}
答案 6 :(得分：-3)
您要输入密码吗？
_________________ ERROR at setup of test_myfunc[10-clean_data] _________________
self = <_pytest.python.CallSpec2 object at 0x7f8a4ff06518>, name = 'shape'
def getparam(self, name):
try:
> return self.params[name]
E KeyError: 'shape'
/usr/lib/python3.6/site-packages/_pytest/python.py:684: KeyError
During handling of the above exception, another exception occurred:
self = <SubRequest 'clean_data' for <Function 'test_myfunc[10-clean_data]'>>
fixturedef = <FixtureDef name='shape' scope='function' baseid='pytest-parametrized.py' >
def _compute_fixture_value(self, fixturedef):
"""
Creates a SubRequest based on "self" and calls the execute method of the given fixturedef object. This will
force the FixtureDef object to throw away any previous results and compute a new fixture value, which
will be stored into the FixtureDef object itself.
:param FixtureDef fixturedef:
"""
# prepare a subrequest object before calling fixture function
# (latter managed by fixturedef)
argname = fixturedef.argname
funcitem = self._pyfuncitem
scope = fixturedef.scope
try:
> param = funcitem.callspec.getparam(argname)
/usr/lib/python3.6/site-packages/_pytest/fixtures.py:484:
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
self = <_pytest.python.CallSpec2 object at 0x7f8a4ff06518>, name = 'shape'
def getparam(self, name):
try:
return self.params[name]
except KeyError:
if self._globalparam is NOTSET:
> raise ValueError(name)
E ValueError: shape
/usr/lib/python3.6/site-packages/_pytest/python.py:687: ValueError
During handling of the above exception, another exception occurred:
request = <SubRequest 'data' for <Function 'test_myfunc[10-clean_data]'>>
@pytest.fixture()
def data(request):
""" Get the appropriate datset based on the request """
> return request.getfuncargvalue(request.param)
pytest-parametrized.py:55:
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
/usr/lib/python3.6/site-packages/_pytest/fixtures.py:439: in getfuncargvalue
return self.getfixturevalue(argname)
/usr/lib/python3.6/site-packages/_pytest/fixtures.py:430: in getfixturevalue
return self._get_active_fixturedef(argname).cached_result[0]
/usr/lib/python3.6/site-packages/_pytest/fixtures.py:455: in _get_active_fixturedef
self._compute_fixture_value(fixturedef)
/usr/lib/python3.6/site-packages/_pytest/fixtures.py:526: in _compute_fixture_value
fixturedef.execute(request=subrequest)
/usr/lib/python3.6/site-packages/_pytest/fixtures.py:778: in execute
fixturedef = request._get_active_fixturedef(argname)
/usr/lib/python3.6/site-packages/_pytest/fixtures.py:455: in _get_active_fixturedef
self._compute_fixture_value(fixturedef)
_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _
self = <SubRequest 'clean_data' for <Function 'test_myfunc[10-clean_data]'>>
fixturedef = <FixtureDef name='shape' scope='function' baseid='pytest-parametrized.py' >
def _compute_fixture_value(self, fixturedef):
"""
Creates a SubRequest based on "self" and calls the execute method of the given fixturedef object. This will
force the FixtureDef object to throw away any previous results and compute a new fixture value, which
will be stored into the FixtureDef object itself.
:param FixtureDef fixturedef:
"""
# prepare a subrequest object before calling fixture function
# (latter managed by fixturedef)
argname = fixturedef.argname
funcitem = self._pyfuncitem
scope = fixturedef.scope
try:
param = funcitem.callspec.getparam(argname)
except (AttributeError, ValueError):
param = NOTSET
param_index = 0
if fixturedef.params is not None:
frame = inspect.stack()[3]
frameinfo = inspect.getframeinfo(frame[0])
source_path = frameinfo.filename
source_lineno = frameinfo.lineno
source_path = py.path.local(source_path)
if source_path.relto(funcitem.config.rootdir):
source_path = source_path.relto(funcitem.config.rootdir)
msg = (
"The requested fixture has no parameter defined for the "
"current test.\n\nRequested fixture '{0}' defined in:\n{1}"
"\n\nRequested here:\n{2}:{3}".format(
fixturedef.argname,
getlocation(fixturedef.func, funcitem.config.rootdir),
source_path,
source_lineno,
)
)
> fail(msg)
E Failed: The requested fixture has no parameter defined for the current test.
E
E Requested fixture 'shape' defined in:
E pytest-parametrized.py:27
E
E Requested here:
E /usr/lib/python3.6/site-packages/_pytest/fixtures.py:526
/usr/lib/python3.6/site-packages/_pytest/fixtures.py:506: Failed