Question

我有一个名为plt.total的数据框，它由5行（ob）和7列（变量）组成，如下所示：

set.seed(2018)
plt.total <- data.frame(replicate(7,runif(5, min=0.80, max=0.9)))
colnames(plt.total) <- c("R", paste0("Matrix",1:6))
plt.total[,1] <- c(1:5)

然后我使用plotly对其进行绘制，如下所示：

plot_ly(data=plt.total, x = ~R, y = ~Matrix1, name = 'Matrix 1', type = 'scatter', mode = 'lines',
                  line = list(color = 'rgb(205, 12, 24)', width = 3, dash = 'dashdot')) %>%
        add_trace(y = ~Matrix2, name = 'Matrix 2', line = list(color = 'rgb(22, 96, 167)', width = 3, dash = 'solid' )) %>%
        add_trace(y = ~Matrix3, name = 'Matrix 3', line = list(color = 'rgb(205, 12, 24)', width = 3, dash = 'longdashdot')) %>%
        add_trace(y = ~Matrix4, name = 'Matrix 4', line = list(color = 'rgb(22, 96, 167)', width = 3, dash = 'dash')) %>%
        add_trace(y = ~Matrix5, name = 'Matrix 5', line = list(color = 'rgb(205, 12, 24)', width = 3, dash = 'dot')) %>%
        add_trace(y = ~Matrix6, name = 'Matrix 6', line = list(color = 'rgb(22, 96, 167)', width = 3, dash = 'dot')) %>%
layout(title = "", legend = list(x=0, y=0, font = list(family = "Times", size = 14, color = "#000")))

但是，我的问题是plt.total会不时更改“列”的数量，因此我试图找到一种避免每次都修改脚本的方法（使用add_trace）。因此，我的目标是使用plotly绘制数据帧每一列的输入，而与列数无关。

谢谢

Answer 1

一种方法是将plt.total表转换为长而整洁的格式，以便您可以映射到矩阵号，而不必手动添加单独的序列。

在这里，我们将数据的形状更改为较长的形状，并使用新的“矩阵”字段来表示观测值属于哪个系列。

plt.total.tidy <-
  plt.total %>%
  tidyr::gather(matrix, value, -R)

我的plotly-fu还不是很好，所以这里我先在ggplot中制作图表，然后使用plotly::ggplotly将其移植到plotly中，并添加您所做的布局选择。如果您想手动指定颜色和线型，而不是为它们指定颜色和线型，则可以使用scale_color_manual和scale_linetype_manual函数来实现。

library(ggplot2)
p <- ggplot(plt.total.tidy, aes(R, value, color = matrix, lty = matrix)) +
  geom_line(size = 1.1) +
  theme(legend.position = c(0.1,0.1)) #+   
  # Could add below lines if you want to manually pick colors and linetypes
  # scale_color_manual(....) +
  # scale_linetype_manual(....) +

ggplotly(p) %>%
  layout(title = "", legend = list(x=0, y=0, font = list(family = "Times", size = 14, color = "#000")))

Answer 2

我设法使用列表而不是数据框，如下所示。也许有人知道更好的方法？

set.seed(2018)
plt.total <- list()
n <- 10 # number of lines in the plot
for (i in 1:n) {
    plt.total[i] <- list(
    list(x=c(1:5), y=replicate(1,runif(5, min=0.80, max=0.9)), color=randomcoloR::randomColor(n, luminosity="light")))
}

p <- plot_ly()
p
for(i in 1:length(plt.total)) {  p <- add_trace(p, y=plt.total[[i]]$y, 
                                                   x=plt.total[[i]]$x, line=list(color=plt.total[[i]]$color), 
                                                   name=paste0("Matrix",i), mode = "lines")%>%
                                          layout(title = "", legend = list(x=0, y=0, 
                                                   font = list(family = "Times", 
                                                   size = 14, color = "#000")),
                                          xaxis = list(title = "R Value", showline = TRUE, 
                                                   annotations= x, range=c(1, 5), linewidth = 2, mirror = "ticks",
                                                   titlefont = list(family = "Times", size = 18, color = "#000"), 
                                                   tickfont = list(family = "Times", size = 14, color = "#000")),
                                          yaxis = list (title = "Value", showline = TRUE, 
                                                   linewidth = 2,mirror = "ticks", 
                                                   titlefont = list(family = "Times", size = 18, color = "#000"), 
                                                   tickfont = list(family = "Times", size = 14, color = "#000")) )
}
p

不管列数如何，都使用plotly（）绘制数据框的列

2 个答案: