扫描仪在输入后抛出java.util.NoSuchElementException

时间:2018-09-07 09:57:40

标签: java java.util.scanner nosuchelementexception

下面的这段代码将NoSuchElementException抛出到函数aVeryBigSum中。 PS:这是hackerrank的任务,因此我只能修改函数aVeryBigSum中的代码。

此函数接受以下输入:n是要添加的数组中元素的数量,以及数组中的元素。

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

    // Complete the aVeryBigSum function below.
    static long aVeryBigSum(long[] ar) {
        int n, sum = 0;
        Scanner read = new Scanner(System.in);
        n = read.nextInt();
        for(int i = 0; i < n; i++)
            sum += read.nextLong();
        return sum;
    }

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) throws IOException {
        BufferedWriter bufferedWriter
                = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

        int arCount = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        long[] ar = new long[arCount];

        String[] arItems = scanner.nextLine().split(" ");
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        for (int i = 0; i < arCount; i++) {
            long arItem = Long.parseLong(arItems[i]);
            ar[i] = arItem;
        }

        long result = aVeryBigSum(ar);

        bufferedWriter.write(String.valueOf(result));
        bufferedWriter.newLine();

        bufferedWriter.close();

        scanner.close();
    }
}

输出: enter image description here

2 个答案:

答案 0 :(得分:2)

为什么要通过Scanner方法从aVeryBigSum中读取内容?

只需遍历ar参数并计算总和。

static long aVeryBigSum(long[] ar) {
    long _sum = 0;
    for(int i=0; i < ar.length; i++)
        sum += ar[i];
    return _sum;
}

答案 1 :(得分:0)

static long aVeryBigSum(long[] ar) {
    int n;
    Long sum = 0;
    Scanner read = new Scanner(System.in);
    n = read.nextInt();
    for(int i = 0; i < n; i++)
        sum += read.nextLong();
    return sum;
}

如果您进行更改,它对我来说很好用:int n;     长和== 0;在现有代码中尝试。

输出:2 1 2

5 1000000001 1000000002 1000000003 1000000004 1000000005 5000000015