Question

select * from `users` 
where exists (
    select *, (6371 * acos(cos(radians(22.559648)) * cos(radians(`lat`)) * cos(radians(`lng`) - radians(88.415552)) + sin(radians(22.559648)) * sin(radians(`lat`)))) AS distances 
    from `locations` 
    where `users`.`location_id` = `locations`.`id` 
    and (6371 * acos(cos(radians(22.559648)) * cos(radians(`lat`)) * cos(radians(`lng`) - radians(88.415552)) + sin(radians(22.559648)) * sin(radians(`lat`)))) < 32.688888 
    ORDER BY `distances` DESC)

Answer 1

您需要在主查询中输入ORDER BY。子查询仅用于判断行是否存在，顺序无关紧要。

但是distances不是主查询中的一列，因此您不能通过编写的查询对其进行排序。您无需使用EXISTS，而需要与子查询联接。

SELECT u.*, (6371 * acos(cos(radians(22.559648)) * cos(radians(`lat`)) * cos(radians(`lng`) - radians(88.415552)) + sin(radians(22.559648)) * sin(radians(`lat`)))) AS distances 
FROM users AS u
JOIN locations AS l ON `u`.`location_id` = `l`.`id` 
HAVING distances < 32.688888 
ORDER BY distances DESC

尝试通过升序获取距离时ORDER BY无法正常工作

1 个答案: