订单表结果按日期升序 - 不工作

时间:2013-01-13 13:30:02

标签: php mysql date

试图在别处找到答案,但没有成功。任何想要纠正我的人,我确信我遗漏了一些基本的东西 - 我找不到什么。

我有11个列的表'数据',inc'from_Date'和to_date'。目前正在显示的结果是日期最远的未来。我要求结果首先显示为最接近的日期(即ASC/DESC)。

尝试ORDER BY from_date - 没有效果。样本数据/页面'结果在my search表格代码(参考)

<form action="webdeals.php" method="post" name="form1" id="form1" style="margin-bottom: 0;">
  <table width="839" border="0">
    <tr valign="top">
      <td width="83">&nbsp;</td>
      <td width="105"><span class="style31">Course Type:</span>
      </td>
      <td width="161">
        <select name="city">
          <option value="">--</option>
          <?php $sql="SELECT * FROM " .$SETTINGS[ "data_table"].
          " GROUP BY city ORDER BY city"; $sql_result=m ysql_query ($sql, $connection ) or die (
          'request "Could not execute SQL query" '.$sql); while ($row=m ysql_fetch_assoc($sql_result)) { echo
          "<option value='".$row[ "city"]. "'
    ".($row[ "city"]==$_REQUEST[ "city"] ? "selected" : ""). ">".$row[
          "city"]. "</option>"; } ?>
        </select>
      </td>
      <td width="100" class="style27"><span class="style31">From:</span>
      </td>
      <td width="108">
        <input name="from" type="text" id="from" size="10" value="
    <?php echo $_REQUEST   [" from "]; ?>" />
      </td>
      <td width="104">
        <img src="images/calendar_icon_pack.png" width="32" height="32" />
      </td>
      <td width="153">
        <div align="center">
          <input type="image" src="http://www.scotsail.co.uk/images/filter_button.png"
          alt="Refine Results" />
        </div>
      </td>
    </tr>
    <tr valign="top">
      <td class="style23">&nbsp;</td>
      <td class="style31">Price Search:</td>
      <td>
        <input type="text" name="string" id="string" value="
    <?php echo stripcslashes($_REQUEST[" string "]); ?>" />
      </td>
      <td>
        <label for="to2" class="style31">To:</label>
      </td>
      <td>
        <input name="to" type="text" id="to" size="10" value="<?php echo $_REQUEST["
        to "]; ?>"/>
      </td>
      <td>
        <img src="images/calendar_icon_pack.png" width="32" height="32" />
      </td>
      <td>
        <div align="center"><a href="webdeals.php">Reset</a>
        </div>
      </td>
    </tr>
  </table>
  <label for="from" class="style2"></label>
</form>

然后:

<?php 

if ($_REQUEST[ "string"]<>'') {
    $search_string = " AND (full_name LIKE '%".mysql_real_escape_string($_REQUEST["string"])."%' OR email LIKE '%".mysql_real_escape_string($_REQUEST["string"])."%')";
}


if ($_REQUEST["city"]<>'') {
    $search_city = " AND city='".mysql_real_escape_string($_REQUEST["city"])."'";
}


if ($_REQUEST["from"]  <>'' and $_REQUEST["to"]    <>'') {
    $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE from_date
  >= ' ".mysql_real_escape_string($_REQUEST["from"])."' AND to_date
  <='".mysql_real_escape_string     ($_REQUEST["to"])."' ".$search_string.$search_city;
} else
if ($_REQUEST["from "]<>'') {
    $sql = "SELECT * FROM ".$SETTINGS["data_table "]." WHERE from_date>= ' ".mysql_real_escape_string ($_REQUEST["from"])."'".$search_string.$search_city;
} else
if ($_REQUEST["to"]        <>'') {
    $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE to_date
      <='".mysql_real_escape_string    ($_REQUEST["to"])."' ".$search_string.$search_city;
} else {
    $sql = "SELECT * FROM ".$SETTINGS["data_table "]." WHERE id>0".$search_string.$search_city;
}

$sql_result = mysql_query ($sql, $connection            ) or die ('request "Could not execute SQL query" '.$sql);

if (mysql_num_rows($sql_result)>0)            {
    while ($row = mysql_fetch_assoc($sql_result)) {
        ?>

如果这是一个基本问题,请道歉,但是因为无法使它发挥作用而感到遗憾。


更新: 感谢@Veger和其他人的评论。

} else { 
    $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE id>0 ORDER BY from_date ".$search_string.$search_city;
}

确实会导致“未定义”结果按from_date排序,但是这会打破“city”列/字段的搜索,并且在调用from_date和to_date时不起作用。关于它应该如何看待的任何想法?

1 个答案:

答案 0 :(得分:0)

你在$string_string语句之后添加了ORDER BY,这会导致错误的SQL查询:

SELECT * FROM <table> 
  WHERE id>0 
  ORDER BY from_date AND (full_name LIKE '%<fullname>%')

你需要交换两者:

$sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE id>0 ".$search_string.$search_city." ORDER BY from_date";

所以你的查询就像:

    SELECT * FROM <table> 
      WHERE id>0 AND (full_name LIKE '%<fullname>%')
      ORDER BY from_date

有关ORDER BY语法和语句排序的更多信息,请查看mysql ORDER BYdocumentation