Question

你好，我在编写的函数中有一行，我无法找出错误所在。我编写了带有命令行解析的函数，尽管我未添加-a命令，但我编写的可选函数之一仍在运行。它无需我指定使用-a即可完成我想要执行的所有操作。

def parse_command_line():
"""
Parse the command line arguments and return the parse_args object.

There should be 1 positional argument and 6 optional arguments.
The help message generated by the parser should look like:

usage: cipher.py [-h] [-o outfile_path] [-k KEY] [-d] [-a] [-v] infile

positional arguments:
  infile                input file to be encrypted or decrypted

optional arguments:
  -h, --help            show this help message and exit
  -o outfile_path, --outfile outfile_path
                        output file
  -k KEY, --key KEY     encryption/decryption key (must be positive) (default
                        = 1)
  -d, --decrypt         decrypt the input file
  -a, --all             decrypt using all keys [1, 25], save outputs in
                        different files. (useful in case the key is lost or
                        unknown)
  -v, --verbose         verbose mode


args:
    None

returns:
    args: generated argparse object with all the passed command line arguments      
"""

parser = argparse.ArgumentParser()

#parser.add_argument('infile', type = str, help = 'input file to be encrypted of decrypted')


#parser.add_argument('-h', '--help', help = 'show this help message and exit')
parser.add_argument('-o', '--outfile', help = 'output file')
parser.add_argument('-k', '--key', default = 1, help = 'encryption/decryption key (must be postive) (default = 1)')
parser.add_argument('-d', '--decrypt', action = 'store_true', help = 'decrypt the input file')
parser.add_argument('-a', '--all', action = 'store_true', default = [1, 25], help = 'decrypt using all keys [1, 25], save outputs in diferent files. (useful in case the key is lost of unknown)')
parser.add_argument('-v', '--verbose', action = 'store_true', help = 'verbose mode')

parser.add_argument('infile', help = 'input file to be encrypted of decrypted')

args = parser.parse_args()
print('args:', args)
return args

程序更长，但是每次我从命令行运行测试命令时，它都会尝试使用每个密钥解密所有内容并将每个密钥保存到文件中。

%%bash

python3 cipher.py plain_message.txt -k 23 -v -o cipher_message.txt

我还有更多错误要调试，但是即使参数是可选的并且上面的语句中也缺少该参数，我也不明白为什么默认值仍在运行。我希望我不会在这里错过真正明显的东西。 -谢谢

可选的命令行解析

0 个答案: