Question

我正在尝试使用Python编写自己的四联游戏。我正在尝试将绘制的圆排序为2d数组。但是，当我尝试将形状对象分配给数组时，它给了我一个索引错误。我真的看不到计数器行和计数列的问题，还有其他人可以吗？顺便说一句，我的太空舱只有一个初始化程序设置x1，x2，y1，y2，take和id

from tkinter import *
from space import *

master = Tk();
w = Canvas(master, width = 600, height = 500)
w.pack()

spaceList = []
for i in range(7):
    spaceList.append([0] * 6)
currentmove = 'PLAYER1'
won = False
counterrow = 0
countercolumn = 0

for i in range(0,560,80):
    for j in range(0,480,80):
        w.create_oval(10+i, 10+j, 90+i, 90+j)
        newspace = Space(10+i, 10+j, 90+i, 90+j, False, 'EMPTY')
        spaceList[counterrow][countercolumn] = newspace
        countercolumn = countercolumn + 1
    counterrow = counterrow + 1

while(not won):
    movecol = int(input("Please select a column!"))

def move(column):
    for i in spaceList:
        return 0

mainloop()

Answer 1

您必须重置对应列：

for i in range(0,560,80):
    # add this:
    countercolumn = 0
    for j in range(0,480,80):
        # omitted

否则它将变为7或更大，并且您会溢出。

制作游戏时二维数组索引Python的问题

1 个答案: