Question

这里是新程序员-我正在尝试创建一个猜数字游戏。如果我猜得太高，它会告诉我“太高，请再猜一次”。如果我猜得太低，它会告诉我“太低，请再猜一次”。如果我猜对了，那就告诉我正确。但是我只能在每个方向上猜出1个错误的答案。我已经搜索并搜索并尝试了几乎所有内容（如果/其他/同时）

我知道这可能是有经验的程序员的简单解决方案。请帮忙。谢谢---

var secretNumber = 53;

var guess = prompt('Guess a number');


if (guess == (53)) {
alert("Yes you got it! 53 is the right answer!")}

while (guess < (53)) {
var guess = prompt('Too Low, Guess again');
}

while (guess > (53)) {
var guess = prompt('Too High, Guess again');
}

Answer 1

尝试一下：

var secretNumber = 53;

var high = false;
var low = false;
var done = false;

var guess = prompt('Guess a number');
while (!done) {
  if (guess === secretNumber) {
    alert("Yes you got it! " + secretNumber + " is the right answer!");
    done = true;
  } else if (guess < secretNumber) {
    if (low) {
      alert('You have failed');
      done = true;
    } else {
      low = true;
      guess = prompt('Too Low, Guess again');
    }
  } else if (guess > secretNumber) {
    if (high) {
      alert('You have failed');
      done = true;
    } else {
      high = true;
      guess = prompt('Too High, Guess again');
    }
  }
}

这不是最佳选择，但对于本练习应该如此。

如何循环我的问题？ Javascript猜数字游戏

1 个答案: