Question

好的，除了写一个超时之外我几乎完成了所有事情，如果他们在10秒钟内没有按下Guess按钮，他们会询问用户是否要停止游戏。如果用户选择“确定”，请关闭Web浏览器窗口。我无法弄清楚这是我到目前为止所做的。

<!DOCTYPE html PUBLIC
"-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<HTML>
<HEAD>
<TITLE>Guess the number</TITLE>
<SCRIPT LANGUAGE="JavaScript">
<!-- HIDE FROM INCOMPATIBLE BROWSERS
hiddenNumber = Math.round((Math.random() * 100))%100 + 1;
function checkGuess(obj) {
    var status;
    var guess=obj.value;
    if (guess > hiddenNumber) {
        status=(guess+" is Too high!\nTry again");
    }
    else if (guess < hiddenNumber) {
        status=(guess+" is Too low!\nTry again");
    }
    else if (guess == hiddenNumber){
        status=("Congratulations! You guessed the number!\n"+guess);
    }
    alert(status);
    obj.value='';
}
function continueGame(){
    var quit = confirm("Do you want to stop playing?");
    if (quit == true)
        window.close();
}
// STOP HIDING FROM INCOMPATIBLE BROWSERS -->
</SCRIPT>
</HEAD>
<BODY>
<H1>Guessing Game</H1>
Guess a number between 1 - 100:
<FORM NAME="guessForm">
<INPUT TYPE="text" NAME="guessField">
<INPUT TYPE="button" VALUE=" Guess "
onClick="checkGuess(document.guessForm.guessField);">
</FORM>
</BODY>
</HTML>

Answer 1

timeout=setTimeout(checkExit,10*1000);

if (/*pressed on guess*/)
{
   clearTimeout(timeout);
   timeout=setTimeout(checkExit,10*1000);
}

function checkExit()
{
   if (confirm("Exit?")) window.close();
   else //reset timeout here again
}

Answer 2

如果在代码中添加它，十秒后将继续运行continueGame（）函数：

var t = setTimeout("continueGame()",10000);

猜数游戏

2 个答案: