我是python的初学者。我想从python中的50个输入文本文件中写入50个输出文件。 例如,我有输入文本文件,例如:
bottom_0cm_Box_0_B_90_wave_1.txt
bottom_0cm_Box_45_B_135_wave_1.txt
bottom_0cm_Box_90_B_180_wave_1.txt
...
top_0cm_Box_0_B_90_wave_1.txt
top_0cm_Box_45_B_135_wave_1.txt
top_0cm_Box_90_B_180_wave_1.txt
...
在一个文件中,我有1000个事件,我必须为每个事件做一些计算,因此我要遍历所有1000个事件。 我有以下代码:
file = glob.glob("/position/*.txt")
print file
print len(file)
for f in file:
with open(f, 'rb') as input:
all_lines = [line for line in input]
x = np.arange(1,1025) #x value is common for all the events
Amplitude=list()
for j in range(1,1000):
y2 = np.array(all_lines[1032*j+8:1032*(j+1)],dtype=float)
x22 = list(x)
y2_=list(y2)
y22 = [((i / 4096)-0.5) for i in y2_]
min_y2 = min(y22) # Find the maximum y2 value
index_min_y2 = y22.index(min_y2) #index for minimum of y2
min_x2 = x[y22.index(min_y2)]
print 'minimum x2', min_x2, 'minimum y2', min_y2
Amplitude.append(round(min_y2, 2))
with open ('bottom_0cm_Box_0_B_90_amplitude.txt', 'w') as fo:
for d in Amplitude:
fo.write(str(d) + '\n')
我要写:
bottom_0cm_Box_0_B_90_amplitude.txt
的{{1}}的输入文本文件。bottom_0cm_Box_0_B_90_wave_1.txt
的{{1}} 以此类推。
答案 0 :(得分:0)
您可以将输入文件的名称分为基础名称和扩展名,用不同的后缀替换基础名称,将它们连接为全名,然后将基础名称与新的目录名称结合起来以获得完整路径名称。
添加:
import os.path
然后更改:
with open ('bottom_0cm_Box_0_B_90_amplitude.txt', 'w') as fo:
收件人:
basename, ext = os.path.splitext(os.path.basename(f))
basename = basename[:-len('wave_1')] + 'amplitude'
with open (os.path.join(new_dir, basename + ext), 'w') as fo:
此外,您不需要将所有结果保存到Amplitude
列表中,因为之后要做的就是将其转储到文件中。相反,您应该将要追加到Amplitude
的内容直接写到输出文件中以节省内存:
import os.path
import glob
file = glob.glob("/position/*.txt")
print file
print len(file)
for f in file:
with open(f, 'rb') as input:
all_lines = [line for line in input]
x = np.arange(1,1025) #x value is common for all the events
basename, ext = os.path.splitext(os.path.basename(f))
basename = basename[:-len('wave_1')] + 'amplitude'
with open(os.path.join(new_dir, basename + ext), 'w') as fo:
for j in range(1,1000):
y2 = np.array(all_lines[1032*j+8:1032*(j+1)],dtype=float)
x22 = list(x)
y2_=list(y2)
y22 = [((i / 4096)-0.5) for i in y2_]
min_y2 = min(y22) # Find the maximum y2 value
index_min_y2 = y22.index(min_y2) #index for minimum of y2
min_x2 = x[y22.index(min_y2)]
print 'minimum x2', min_x2, 'minimum y2', min_y2
fo.write(str(round(min_y2, 2)) + '\n')