我已将字符串存储在变量中。我想将它附加到文本文件中。我怎样才能做到这一点?
def readyaml(abs_read_path,):
with open(abs_read_path, 'r') as stream, open("instanceinput.txt",'w') as fnew:
try:
content = yaml.load(stream)
instance = content['instance']
dump = instance[0]
print dump
fnew.write(dump)
except yaml.YAMLError as exc:
print(exc)
stream.close()
fnew.close()
readyaml(abs_read_path)
答案 0 :(得分:2)
使用a
代替w
:
with open(abs_read_path, 'r') as stream, open("instanceinput.txt",'a') as fnew:
答案 1 :(得分:2)
您需要使用追加方法 Vikas& Mayur提到了,并且当写入文件时将其转换为sting对象:
示例:
def readyaml(abs_read_path,):
with open(abs_read_path, 'r') as stream, open("instanceinput.txt",'a') as fnew:
try:
content = yaml.load(stream)
instance = content['instance']
dump = instance[0]
print dump
fnew.write(str(dump)) # CONVERT TO STRING OBJECT
except yaml.YAMLError as exc:
print(exc)
stream.close()
fnew.close()
readyaml(abs_read_path)
答案 2 :(得分:1)
您可以使用'a'
或'a+'
代替'w'
'a'
如果文件不存在,则创建该文件。
打开写入并附加数据。
'a+'
如果文件不存在,则创建该文件。
打开读取和写入,并在写入时附加数据。