Question

我想对字符串进行分块以使组处于特定高度。应保留原始顺序，并应完全包含所有原始单词。

import nltk 
height = 2
sentence = [("the", "DT"), ("little", "JJ"), ("yellow", "JJ"), ("dog", "NN"), ("barked","VBD"), ("at", "IN"), ("the", "DT"), ("cat", "NN")]

pattern = """NP: {<DT>?<JJ>*<NN>}
VBD: {<VBD>}
IN: {<IN>}"""
NPChunker = nltk.RegexpParser(pattern) 
result = NPChunker.parse(sentence)

In [29]: Tree.fromstring(str(result)).pretty_print()
                             S                                      
            _________________|_____________________________          
           NP                        VBD       IN          NP       
   ________|_________________         |        |      _____|____     
the/DT little/JJ yellow/JJ dog/NN barked/VBD at/IN the/DT     cat/NN

我的方法有点像下面这样的蛮力：

In [30]: [list(map(lambda x: x[0], _tree.leaves())) for _tree in result.subtrees(lambda x: x.height()==height)]
Out[30]: [['the', 'little', 'yellow', 'dog'], ['barked'], ['at'], ['the', 'cat']]

我认为应该存在一些直接的API或可以用于分块的东西。任何建议都将受到高度赞赏。

Answer 1

不是，NLTK中没有任何内置函数可以返回一定深度的Tree。

但是您可以使用How to Traverse an NLTK Tree object?

中的深度优先遍历

为了提高效率，您可以迭代深度优先，并且仅在深度小于必要深度（例如

import nltk 
sentence = [("the", "DT"), ("little", "JJ"), ("yellow", "JJ"), ("dog", "NN"), ("barked","VBD"), ("at", "IN"), ("the", "DT"), ("cat", "NN")]

pattern = """NP: {<DT>?<JJ>*<NN>}
VBD: {<VBD>}
IN: {<IN>}"""
NPChunker = nltk.RegexpParser(pattern) 
result = NPChunker.parse(sentence)

def traverse_tree(tree, depth=float('inf')):
    """ 
    Traversing the Tree depth-first,
    yield leaves up to `depth` level.
    """
    for subtree in tree:
        if type(subtree) == nltk.tree.Tree:
            if subtree.height() <= depth:
                yield subtree.leaves()
                traverse_tree(subtree)


list(traverse_tree(result, 2))

[输出]：

[[('the', 'DT'), ('little', 'JJ'), ('yellow', 'JJ'), ('dog', 'NN')],
 [('barked', 'VBD')],
 [('at', 'IN')],
 [('the', 'DT'), ('cat', 'NN')]]

另一个例子：

x = """(S
  (NP the/DT 
      (AP little/JJ yellow/JJ)
       dog/NN)
  (VBD barked/VBD)
  (IN at/IN)
  (NP the/DT cat/NN))"""

list(traverse_tree(Tree.fromstring(x), 2))

[输出]：

[['barked/VBD'], ['at/IN'], ['the/DT', 'cat/NN']]

从nltk树中获取分块结果的任何好方法，好方法或直接方法？

1 个答案: