我在Twitter上抓取了用户名,推文,回复,推文,但无法保存为CSV文件。
这是代码:
new Amazon.EC2.Model.Filter
{
Name = "instance-id",
Values = new List<string>
{
""
}
}
new Amazon.EC2.Model.Filter
{
Name = "instance-id",
Values = new List<string>
{
null
}
}
new Amazon.EC2.Model.Filter
{
Name = "instance-id",
Values = null
}
new Amazon.EC2.Model.Filter
{
Name = "instance-id",
Values = new List<string>
{
"!*"
}
}
我获取了数据,但是无法保存在CSV文件中。有人向我解释了如何将数据保存为CSV文件。
答案 0 :(得分:2)
如您所见,您在tweets = soup.find_all("div", {"class":"js-stream-item"})
上找到推文时只犯了一个小错误,却忘记传递应该像这样的tweets = soup.find_all("div", attrs={"class":"js-stream-item"})
的自变量键名
from urllib.request import urlopen
from bs4 import BeautifulSoup
file = "5_twitterBBC.csv"
f = open(file, "w")
Headers = "tweet_user, tweet_text, replies, retweets\n"
f.write(Headers)
url = "https://twitter.com/BBCWorld"
html = urlopen(url)
soup = BeautifulSoup(html, "html.parser")
# Gets the tweet
tweets = soup.find_all("li", attrs={"class":"js-stream-item"})
# Writes tweet fetched in file
for tweet in tweets:
try:
if tweet.find('p',{"class":'tweet-text'}):
tweet_user = tweet.find('span',{"class":'username'}).text.strip()
tweet_text = tweet.find('p',{"class":'tweet-text'}).text.encode('utf8').strip()
replies = tweet.find('span',{"class":"ProfileTweet-actionCount"}).text.strip()
retweets = tweet.find('span', {"class" : "ProfileTweet-action--retweet"}).text.strip()
# String interpolation technique
f.write(f'{tweet_user},/^{tweet_text}$/,{replies},{retweets}\n')
except: AttributeError
f.close()
答案 1 :(得分:0)
filename = "output.csv"
f = open(filename, "w",encoding="utf-8")
headers = " tweet_user, tweet_text, replies, retweets \n"
f.write(headers)
***your code***
***loop****
f.write(''.join(tweet_user + [","] + tweet_text + [","] + replies + [","] + retweets + [","] + ["\n"]) )
f.close()