Question

我是BeautifulSoup4的新手，无法从以下代码的html响应中提取纬度和经度值。

url = 'http://cinematreasures.org/theaters/united-states?page=1' 
r = requests.get(url)
soup = BeautifulSoup(r.content)
links = soup.findAll("tr")
print links

此代码多次打印出此响应。

<tr class="even location theater" data="{id: 0, point: {lng: -94.1751038, lat: 36.0848965}

完整回复

<tr>\n
  <th id="theater_name"><a href="/theaters/united-states?sort=name&amp;order=desc">\u2191 Name</a>
  </th>\n
  <th id="theater_location"><a href="/theaters/united-states?sort=location&amp;order=asc">Location</a>
  </th>\n
  <th id="theater_status"><a href="/theaters/united-states?sort=open&amp;order=desc">Status</a>
  </th>\n
  <th id="theater_screens"><a href="/theaters/united-states?sort=screens&amp;order=asc">Screens</a>
  </th>\n</tr>,
<tr class="even location theater" data="{id: 0, point: {lng: -94.1751038, lat: 36.0848965}, category: 'open'}">\n
  <td class="name">\n
    <a class="map-link" href="/theaters/8775">
      <img alt="112 Drive-In" height="48" src="http://photos.cinematreasures.org/production/photos/22137/1313612883/thumb.JPG?1313612883" width="48" />
    </a>\n<a class="map-link" href="/theaters/8775">112 Drive-In</a>\n
    <div class="info-box">\n
      <div class="photo" style="float: left;">
        <a href="/theaters/8775">
          <img alt="thumb" height="48" src="http://photos.cinematreasures.org/production/photos/22137/1313612883/thumb.JPG?1313612883" width="48" />
        </a>
      </div>\n
      <p style="min-width: 200px !important;">\n<strong><a href="/theaters/8775">112 Drive-In</a></strong>\n
        <br>\n 3352 Highway 112 North
        <br>Fayetteville, AR 72702
        <br>United States
        <br>479.442.4542
        <br>\n</br>
        </br>
        </br>
        </br>
        </br>
      </p>\n</div>\n</td>\n
  <td class="location">\n Fayetteville, AR, United States\n</td>\n
  <td class="status">\n Open\n</td>\n
  <td class="screens">\n 1\n</td>\n</tr>

我如何从这个响应中获取lng和lat值？

提前谢谢。

Answer 1

这是我的方法：

import requests
import demjson
from bs4 import BeautifulSoup

url = 'http://cinematreasures.org/theaters/united-states?page=1'
page = requests.get(url)
soup = BeautifulSoup(page.text)

to_plain_coord = lambda d: (d['point']['lng'], d['point']['lat'])
# Grabbing theater coords if `data` attribute exists
coords = [
    to_plain_coord(demjson.decode(t.attrs['data']))
    for t in soup.select('.theater')
    if 'data' in t.attrs]

print(coords)

我没有使用任何字符串操作。相反，我从data属性加载JSON。不幸的是，这里的JSON不是很有效，所以我使用demjson库进行json解析。

pip install demjson

Answer 2

好的，所以你正确地抓住了所有<tr>，现在我们只需要从每个{get}获取数据属性。

import re
import requests
from bs4 import BeautifulSoup

url = 'http://cinematreasures.org/theaters/united-states?page=1' 
r = requests.get(url)
soup = BeautifulSoup(r.text, "html.parser")
theaters = soup.findAll("tr", class_="theater")
data = [ t.get('data') for t in theaters if t.get('data') ]
print data

不幸的是，这会给你一个字符串列表，而不是一个人们所希望的字典对象。我们可以在数据字符串上使用正则表达式将它们转换为dicts（感谢RootTwo）：

coords = []
for d in data:
    c = dict(re.findall(r'(lat|lng):\s*(-?\d{1,3}\.\d+)', d))
    coords.append(c)

Answer 3

如果您只期待一次回复，请执行以下操作：

print links[0]

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