我在针对URL中的查询参数进行顺序过滤以在Django Rest Framework中工作时缺少什么？

Question

我试图对this page之后的url中的查询参数实施函数过滤，并且该过滤器在其他环境中也有效。
因此，我试图在其他应用程序中复制此代码。但是，即使我实现了相同的代码，也无法找到如下所示的过滤接口。
有人知道我在想什么吗？

urls.py

router=routers.SimpleRouter()
router.register(r'list',projectViewSet)
urlpatterns = [
    url(r'^api/', include(router.urls)),
]  

views.py

class projectViewSet(viewsets.ModelViewSet):

    """
    This API returns the list of all projects with basic information to be able to filter
    """
    queryset=html.objects.all()
    serializer_class = projectSerializer
    filter_class=projectAPIfilter

serializer.py

class projectSerializer(serializers.ModelSerializer):
    area=areaSerializer(read_only=True)
    unmet=unmetSerializer(read_only=True)
    energy = energySer(read_only=True)

    class Meta:
        model = html
        fields = ('pk', 'project', 'version', 'program', 'location', 'certificate', 'user', 'good', 'final','area','unmet','energy','good','final')

filters.py

class projectAPIfilter(filters.FilterSet):
    user = django_filters.CharFilter(lookup_expr="iexact")
    project = django_filters.CharFilter(lookup_expr="icontains")

    class Meta:
        model=html
        fields=['project','program','location','certificate','user','good','final']

settings.py

REST_FRAMEWORK = {
    'DEFAULT_FILTER_BACKENDS': (
        'django_filters.rest_framework.DjangoFilterBackend',
    ),
    'DEFAULT_PAGINATION_CLASS': 'rest_framework.pagination.LimitOffsetPagination',
    'PAGE_SIZE': 100
}

INSTALLED_APPS = [
    'django.contrib.admin',
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.messages',
    'django.contrib.staticfiles',
    'django.contrib.humanize',
    'corsheaders',
    'rest_framework',
    'rest_framework.authtoken',
    'widget_tweaks',
    'crispy_forms',
    'rest_framework_swagger',
    #'el_pagination',
    'django_tables2',
    'django_filters',
    'heatBalance',
    'project',
    'ecm',
    'help',
    'BEAM',
    'social_django',
    # 'social_django_mongoengine'
]

软件包

django=2.0.4=py35_0  
djangorestframework==3.8.2
django-filter==1.1.0 

更新
根据安吉拉的查询，我尝试输入/ project / api / list /？user = existing-user-uuid，但api返回值似乎没有变化，如下所示。

Answer 1

我尝试如下明确地在views.py中定义过滤器后端。然后问题解决如下图。仍然不知道为什么在settings.py中指定不起作用。但是如果有人遇到同样的问题，这可能是解决问题的一种方法。
views.py

class projectViewSet(viewsets.ModelViewSet):

    """
    This API returns the list of all projects with basic information to be able to filter
    """
    queryset=html.objects.all()
    serializer_class = projectSerializer
    filter_class=projectAPIfilter
    filter_backends = (django_filters.rest_framework.DjangoFilterBackend,)
    pagination_class = projectPagination  

pagination.py

from rest_framework.pagination import PageNumberPagination

class projectPagination(PageNumberPagination):
    page_size = 100