Question

我想从视图中传递来自网址的数据。我读了this并试着写！但是我收到了一个错误：

__init__() takes 1 positional argument but 2 were given

serializer.py:

class ContactsDetailsSerializer(serializers.ModelSerializer):


    class Meta:
        model = Contacts
        fields = ('id', 'profile_id', 'tel','email')

views.py：

class ContactsDetailsViewSet(viewsets.ViewSet):

    def list(self, request ):
        queryset = Contacts.objects.all()
        serializer = ContactsSerializer(queryset, many=True)
        return Response(serializer.data)

urls.py：

  router = routers.DefaultRouter()
    router.register(r'profiles', views.ProfileViewSet)
    # router.register(r'users', views.UserViewSet)
    router.register(r'members', views.MemberViewSet)
    router.register(r'files', views.FilesViewSet)
    router.register(r'contacts', views.ContactsViewSet)
    router.register(r'products', views.ProductsViewSet)
    router.register(r'stories', views.StoriesViewSet)

    urlpatterns = [
        url(r'^admin/', admin.site.urls),
        url(r'^accounts/', include('allauth.urls')),
        url(r'^', include(router.urls)),
         url(r'^test', ContactsDetailsViewSet.as_view({'get': 'list'})),//here
        url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework')),
    ]

任何人都可以提供帮助吗？如何传递数据（通过REST框架）？

Answer 1

{Name:table1 Rows:[{Cols:[{Name:col1 Value:value1} {Name:col2 Value:value2} {Name:col3 Value:value3}]} {Cols:[{Name:col1 Value:value4} {Name:col2 Value:value5} {Name:col3 Value:value6}]}]}
{Name:table2 Rows:[{Cols:[{Name:col1 Value:value7} {Name:col2 Value:value8} {Name:col3 Value:value9} {Name:col4 Value:valueA}]}]}
EOF

您需要使用映射调用url('^test/(?P<profile_id>.+)$', views.ContactsDetailsViewSet),。这不是常规视图，而是ViewSet：

as_view()

另请注意，您需要将url('^test/(?P<profile_id>.+)$', views.ContactsDetailsViewSet).as_view({'get': 'retrieve'})),指定为profile_id。

过滤URL（REST框架）

1 个答案: