Question

我正在使用python并寻求有关如何简化以下代码的帮助。谢谢。

for i in range(1,9):
    if i == 1:
        wt_1 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 2:
        wt_2 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 3:
        wt_3 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 4:
        wt_4 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 5:
        wt_5 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 6:
        wt_6 = gwt_2018[gwt_2018.WkNum == i]
    elif i == 7:
        wt_7 = gwt_2018[gwt_2018.WkNum == i]
    else i == 8:
        wt_8 = gwt_2018[gwt_2018.WkNum == i]

Answer 1

您需要类似的东西吗？

l = [wt_1, wt_2, wt_3, wt_4, wt_5, wt_6, wt_7, wt_8]
for index, i in enumerate(l):
    i = gwt_2018[gwt_2018.WkNum == index+1]

Answer 2

是否必须将'wt_i'作为所有i的变量名？

我会改用字典：

wt = {}
for i in range(1,9):
    wt[i] = gwt_2018[gwt_2018.WkNum == i]

Answer 3

我找到了解决方案[链接]（Create multiple dataframe using for loop in python 2.7）

gbl = globals()
for i in range(1,54):
    gbl['df_'+str(i)] = gwt_2018[gwt_2018.WkNum == i]

简化python中的循环

3 个答案: