Question

如何将用户输入的字符串与数组列表进行比较，然后从数组列表中删除用户字符串字母，这是我的代码：

我想获取用户输入的字符串，例如Apple，然后我要从数组列表中删除字母“ a”，“ p”，“ l”，“ e”。

public static void playgame() {

    ArrayList<String> obj = new ArrayList<String>(
    Arrays.asList("a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z"));

        while(!obj.isEmpty()) {

            System.out.println(name1 + " enter your word:");
            String word1 = reader.nextLine().toLowerCase();
            System.out.println("Enter (y) yes if both players agree on the word and (n) no word is incorrect");
            String y = reader.next();

            String yes = "y";
            String no = "n";

            if(y.equals(yes)) {

                countScore1++;
                char[] wordToString = word1.toCharArray();

                System.out.println(wordToString.length);

                for(int i=0;i<wordToString.length;i++) {

                    String output=Character.toString(wordToString[i]);

                    System.out.println(output);

                        if(obj.contains(output)){
                            obj.remove(output);
                        }   
                }
                System.out.println("Alphabet letters left:" + obj);
                System.out.println("Correct word #######");
            }

Answer 1

请参阅Andy Turner关于单个字符串的消息。实际上，替换

ArrayList<String> obj = new ArrayList<String>(
Arrays.asList("a, b, c, d, e, f, g, h, i, j, k, l, m, n, o, p, q, r, s, t, u, v, w, x, y, z"));

例如与此

List<String> obj = new ArrayList<String>(); 
for(char c = 'a'; c <= 'z'; c++) {
    obj.add(String.valueOf(c));
}

但是，我将使用HashSet而不是ArrayList。我猜HashSet在查找要删除的项目时具有更快的查找算法。

Set<String> obj = new HashSet<String>(); 
for(char c = 'a'; c <= 'z'; c++) {
    obj.add(String.valueOf(c));
}

用户输入的字符串与arraylist

1 个答案: