Question

我正在尝试向MySQL数据库添加影片，这是我的数据库架构：

stopping

这是我的模型课：

Movie.ts

Movie(id, name)
Genre(id, name)
Movie_genre(id_movie, id_genre)

Genre.ts

public class Movie {

    private Short id;
    private String name;
    private List<MovieGenre> movieGenres;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", nullable = false)
    public Short getId() {
        return id;
    }

    public void setId(Short id) {
        this.id = id;
    }

    @Column(name = "name", nullable = false, length = 100)
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @OneToMany(mappedBy = "movie")
    public List<MovieGenre> getMovieGenres() {
        return movieGenres;
    }

    public void setMovieGenres(List<MovieGenre> movieGenres) {
        this.movieGenres = movieGenres;
    }
}

MovieGenre.ts （该模型代表生成的表）

public class Genre {
    private Short id;
    private String name;
    private List<MovieGenre> movieGenres;

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", nullable = false)
    public Short getId() {
        return id;
    }

    public void setId(Short id) {
        this.id = id;
    }

    @Column(name = "name", nullable = false, length = 15)
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @OneToMany(mappedBy = "genre")
    @JsonIgnore
    public List<MovieGenre> getMovieGenres() {
        return movieGenres;
    }

    public void setMovieGenres(List<MovieGenre> movieGenres) {
        this.movieGenres = movieGenres;
    }
}

并且由于我们在最后一个模型中有复合键，因此我们需要一个类：

public class MovieGenre {
    private MovieGenrePK id;
    private Movie movie;
    private Genre genre;

    @EmbeddedId
    @JsonIgnore
    public MovieGenrePK getId() {
        return id;
    }

    public void setId(MovieGenrePK id) {
        this.id = id;
    }

    @MapsId("movieId")
    @ManyToOne
    @JoinColumn(name = "movie_id", referencedColumnName = "id", nullable = false)
    @JsonIgnore
    public Movie getMovie() {
        return movie;
    }

    public void setMovie(Movie movie) {
        this.movie = movie;
    }

    @MapsId("genreId")
    @ManyToOne
    @JoinColumn(name = "genre_id", referencedColumnName = "id", nullable = false)
    public Genre getGenre() {
        return genre;
    }

    public void setGenre(Genre genre) {
        this.genre = genre;
    }
}

因此，我尝试通过发布请求来添加带有流派的电影，首先我发布了一个请求以添加电影，另一个发布了一个请求以添加流派，这很好，现在我需要将一个流派关联到电影。
我尝试了以下方法：
我向以下端点发出了POST请求：public class MovieGenrePK implements Serializable { private Short movieId; private Short genreId; @Column(name = "movie_id", nullable = false) public Short getMovieId() { return movieId; } public void setMovieId(Short movieId) { this.movieId = movieId; } @Column(name = "genre_id", nullable = false) public Short getGenreId() { return genreId; } public void setGenreId(Short genreId) { this.genreId = genreId; } }，具有application / json标头和以下正文：

http://localhost:8080/api/movieGenres

但是我得到了错误：

{
    "movie": "http://localhost:8080/api/movies/6",
    "genre": "http://localhost:8080/api/genres/1"
}

Answer 1

您必须使MovieGenrePK无效，更改：

public class MovieGenre {
    private MovieGenrePK id;
}

到

public class MovieGenre {
    private MovieGenrePK id = new MovieGenrePK();
}

Spring Data REST中具有多对多关系的POST请求

1 个答案: