Question

I've found this exactly same question。但是PyCrypto不会同时安装在python 3.6.5和3.7.0上。

因此，我实现了某种类似于Gronsfeld的密码。我知道，这很糟糕，但是我可以简单地使用密码对字符串进行加密和解密

def encrypt(string, password):
    int_list = []
    password_len = len(password)
    for cnt, sym in enumerate(string):
        password_sym = password[cnt % password_len]
        int_list.append(ord(sym)-ord(password_sym))
    return int_list

# got some list which contain mine key to Todoist api, yes, this can be bruteforced, but same as any other API key
>>> [-20, -20, -50, -14, -61, -54, 2, 0, 32, 27, -51, -21, -54, -53, 4, 3, 29, -14, -51, 29, -10, -6, 1, 4, 28,
       29, -55, -17, -59, -42, 2, 50, -13, -14, -52, -15, -56, -59, -44, 4]

def decrypt(int_list, password):
    output_string = ""
    password_len = len(password)
    for cnt, numb in enumerate(int_list):
        password_sym = password[cnt % password_len]
        output_string += chr(numb+ord(password_sym))
    return output_string

那么，如何正确执行呢？

Answer 1

密码学是一个积极开发的库，提供密码食谱和原语。它支持Python 2.6-2.7，Python 3.3+和PyPy。

安装

$ pip install cryptography

使用高级对称加密配方的示例代码：

from cryptography.fernet import Fernet
key = Fernet.generate_key()
cipher_suite = Fernet(key)
cipher_text = cipher_suite.encrypt(b"A really secret message. Not for prying eyes.")
plain_text = cipher_suite.decrypt(cipher_text)

如何在python 3.7中加密和解密字符串？

1 个答案: