答案 0 :(得分:2)
您可以使用此:
%matplotlib inline
from matplotlib.pyplot import figure
import matplotlib.pyplot as plt
from numpy import arange, sin, pi
t = arange(0.0, 2.0, 0.01)
fig = figure(1)
ax1 = fig.add_subplot(311)
ax1.plot(t, sin(2*pi*t))
ax2 = fig.add_subplot(312)
ax2.plot(t, sin(4*pi*t))
ax3 = fig.add_subplot(313)
ax3.plot(t, sin(4*pi*t)+sin(2*pi*t))
plt.show()
答案 1 :(得分:1)
您已经有两种解决方案。这给了您非常相似的东西。我本可以使它看起来与您的输出完全一样,但其余部分留给您练习。如有任何疑问,请随时问我。此解决方案基于https://matplotlib.org/examples/pylab_examples/finance_work2.html
C:\Users\*your_user_name*\Documents\R\R-3.5.1
输出
答案 2 :(得分:0)
或者“简单”的东西:
import matplotlib.pyplot as plt
import numpy as np
x = np.arange(0,10,0.01)
x2 = np.arange(0,20,0.02)
sin1 = np.sin(x)
sin2 = np.sin(x2)
x2 /= 2
sin3 = sin1+sin2
plt.plot(x,sin3)
plt.show()
答案 3 :(得分:0)
签出这个解决方案,在其中我为波浪制作了动画,并将输出导出为gif文件。 使用matplotlib和numpy。
import numpy as np
from matplotlib import pyplot as plt
from matplotlib.animation import FuncAnimation
plt.style.use('seaborn-pastel')
fig, (ax1, ax2, ax3) = plt.subplots(3, 1, sharex=True, sharey=True)
fig.suptitle('Sine waves')
ax1.set_xlim(0, 4)
ax1.set_ylim(-4, 4)
line1, = ax1.plot([], [], color='r', lw=3)
line2, = ax2.plot([], [], color='g', lw=3)
line3, = ax3.plot([], [], color='b', lw=6)
plt.legend([line1, line2, line3],['sin(x1)', 'sin(x2)', 'sin(x1)+sin(x2)'])
def init():
line1.set_data([], [])
line2.set_data([], [])
line3.set_data([], [])
return line1, line2, line3
def animate(i):
x1 = np.linspace(0, 4, 1000)
y1 = np.sin(2 * np.pi * (1.1*x1 - 0.05 * i))
line1.set_data(x1, y1)
x2 = np.linspace(0, 4, 1000)
y2 = np.sin(2 * np.pi * (1.21 * x2 - 0.04 * i))
line2.set_data(x2, y2)
x3 = np.linspace(0, 4, 1000)
y3 = np.sin(2 * np.pi * (1.1*x3 - 0.05 * i)) + np.sin(2 * np.pi * (1.21 * x3 - 0.04 * i))
line3.set_data(x3, y3)
return line1, line2, line3
anim1 = FuncAnimation(fig, animate, init_func=init,
frames=200, interval=20, blit=True)
anim1.save('sine_wave.gif', writer='imagemagick')