我正试图通过干预在laravel 5.6中上传图像,并且它可以正常工作,唯一的问题是它在数据库中存储的路径像/var/www/Laravel/project/public/uploads/students/1534413021.jpg
一样,我想要的是将其存储为{ {1}}。
这是我的表格
/uploads/students/1534413021.jpg
答案 0 :(得分:0)
在保存时更改路径,如下所示:
$location = public_path('uploads/students/'.$fileName);
为此:
$location = 'uploads/students/'.$fileName;
它将自动转到public/$location
并保存文件,您在数据库中将只包含所需的字符串;
答案 1 :(得分:0)
您应该尝试以下操作:
public function uploadAvatar(Request $request, Student $student)
{
$validatedData = $request->validate([
'avatar' => 'required | mimes:jpeg,jpg,png,bmb,gif,svg',
]);
if ($request->hasFile('avatar')) {
$image = $request->file('avatar');
$fileName = time() . '.' . $image->getClientOriginalExtension();
$location = public_path('uploads/students/');
$uploadImage = Image::make($image->getRealPath())->resize(800,400);
$uploadImage->save($location.'/'.$fileName);
$imageName = public_path('uploads/students/'.$fileName);
$studentUpdate = Student::where('id',$student->id)
->update([
'avatar'=>$imageName,
]);
if ($studentUpdate) {
return redirect()->route('students.profile',$student->id)->with('success','Student Profile Created Successfully');
}else{
return back()->withInput()->with('errors','Error adding new parent.');
}
}
return back()->withInput()->with('errors','PLease Select An Image.');
}