我有一个对象,它有一个属性,用于存储我的laravel项目中驻留在公用文件夹中的图像的路径
if ($request->get('poster_url')) {
$image = $request->get('poster_url');
$filename = time() . '.' . explode('/', explode(':', substr($image, 0, strpos($image, ';')))[1])[1];
Image::make($request->get('poster_url'))->resize(300, 300)->save(public_path('uploads/concert_pictures/') . $filename);
$concert->poster_url = $filename;
}
我想知道在对需要包含图像的对象列表发出get请求时应该如何发送回来。下面是我当前查询的片段,它将返回对象。响应是将在我的前端客户端中使用的json响应。
if (isset($queryParams['search'])) {
$searchParams = $queryParams['search'];
$limit = 10;
$bands = Band::with('genre', 'country')
->where('name', 'LIKE', "%{$searchParams}%")
->orderBy('created_at', 'desc')
->paginate($limit);
} else {
$bands = Band::with('genre', 'country')
->orderBy('created_at', 'desc')
->paginate($limit);
}
角度模板
<ng-container *ngFor="let band of bands">
<div class="col-sm-6 margin-bottom-20" (click)="navigateToBand(band.id)">
<div class="card-group">
<div class="card card-shadow">
<img class="card-img-top"
src="{{band.image_url}}"
alt="Card image cap">
<div class="card-img-overlay">
<h5 class="card-title float-right">{{band.country.name}}</h5>
<ng-container *ngFor="let genre of band.genre; let i = index">
<p class="card-text" *ngIf="i<3">{{genre.type}}</p>
</ng-container>
</div>
<div class="card-body">
<h5 class="card-title">{{band.name}}<span
class="float-right">{{band.price + 'dkk'}}</span></h5>
<p class="card-text">{{band.short_description | slice: 0:80 }} ...</p>
</div>
</div>
</div>
</div>
</ng-container>