Question

我正在做一个面向篮球的乒乓球比赛。我正在尝试将当前具有的矩形更改为篮球运动员精灵，以使其看起来更具吸引力。发生的情况是我的左侧球员完全没有出现，是不可见的，但仍然起着阻挡作用，将球击中。非常感谢任何帮助，谢谢！

import pygame

black = (0,0,0)
white = (255,255,255)

pygame.init()

size = 800,600
screen = pygame.display.set_mode(size)
pygame.display.set_caption("Basketball Shootout")

done = False
clock = pygame.time.Clock()


class Player1(pygame.sprite.Sprite):

    def __init__(self, x, y):
        """Constructor function"""
        # Call the parent's constructor
        super().__init__()

        # Set height, width
        self.image = pygame.Surface([15, 15])
        self.image = pygame.image.load("player1.png")



def player1(x1, y1, xsize, ysize):
    Player1(screen, [x1, y1, xsize, ysize])

def player2(x2, y2, xsize, ysize):
    pygame.draw.rect(screen, black, [x2,y2,xsize,ysize])

def ball(ballx, bally):
    pygame.draw.circle(screen, black, [ballx,bally],20)

def Score1(score1):
    font = pygame.font.Font("Minecraft.ttf" ,50)
    text = font.render(str(score1), True, white)
    screen.blit(text, [160, 550])

def Score2(score2):
    font = pygame.font.Font("Minecraft.ttf" ,50)
    text = font.render(str(score2), True, white)
    screen.blit(text, [610, 550])

x1 = 20
y1 = 175
xsize = 35
ysize = 150
speed1 = 0

x2 = 740
y2 = 175
speed2 = 0

ballx = 550
bally = 250
speedx = 8
speedy = 5

score1 = 0
score2 = 0

bg = pygame.image.load("pongbg2.png")
rect1 = pygame.Rect(50,510,100,50)

def pausescreen():
    import pausescreen


display_game = True
game_page = 1


while not done: 
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            done = True

            pygame.draw.rect(screen, (255, 255, 255), rect1)

        if event.type == pygame.KEYDOWN:
            if event.key == pygame.K_w:
                speed1 = -15
            if event.key == pygame.K_s:
                speed1 = 15
            if event.key == pygame.K_UP:
                speed2 = -15
            if event.key == pygame.K_DOWN:
                speed2 = 15

        if event.type == pygame.KEYUP:
            if event.key == pygame.K_w:
                speed1 = 0
            if event.key == pygame.K_s:
                speed1 = 0
            if event.key == pygame.K_UP:
                speed2 = 0
            if event.key ==  pygame.K_DOWN:
                speed2 = 0
            if event.key == pygame.K_p:
                pausescreen()




    screen.blit(bg, (0, 0))
    player1(x1, y1, xsize, ysize)
    player2(x2, y2, xsize, ysize)
    ball(ballx,bally)
    Score1(score1)
    Score2(score2)

    y1 += speed1
    y2 += speed2
    ballx += speedx
    bally += speedy

    if y1 < 0:
        y1 = 0

    if y1 > 350:
        y1 = 350

    if y2 < 0:
        y2 = 0

    if y2 > 350:
        y2 = 350

    if ballx+20 > x2 and bally-20 > y2 and bally+20 < y2+ysize and ballx < x2+3:
        speedx = -speedx

    if ballx-20 < x1+35 and bally-20 > y1 and bally+20 < y1+ysize and ballx > x1+38:
        speedx = -speedx

    if bally > 477 or bally < 23:
        speedy = -speedy

    if ballx < 13:
        score2 += 1
        ballx = 350
        bally = 250

    if ballx > 750:
        score1 += 1
        ballx = 350
        bally = 250




    pygame.display.flip()

    clock.tick(60)

pygame.quit()

Answer 1

您没有在左侧看到播放器，因为您没有将其绘制到屏幕上。

在大多数情况下，如果您查看代码，这就是所有绘图代码：

screen.blit(bg, (0, 0))
player1(x1, y1, xsize, ysize)
player2(x2, y2, xsize, ysize)
ball(ballx,bally)
Score1(score1)
Score2(score2)

查看完每个功能后，单数为player1，我怀疑是“左边的玩家”。该函数仅调用Player1的构造函数：

def player1(x1, y1, xsize, ysize):
    Player1(screen, [x1, y1, xsize, ysize])

其他人实际上是一些东西，例如player2：

def player2(x2, y2, xsize, ysize):
    pygame.draw.rect(screen, black, [x2,y2,xsize,ysize])

所以我的猜测是：将功能player1更改为pygame.draw.rect(screen, x1, y1, xsize, ysize)。

编辑：如果要绘制要在Player1类中加载的图像，请尝试以下代码：

class Player1(pygame.sprite.Sprite):

    def __init__(self, x, y):
        """Constructor function"""
        # Call the parent's constructor
        super().__init__()

        # Set height, width
        self.image = pygame.Surface([15, 15])
        self.image = pygame.image.load("player1.png")

    def draw(self, x1, y1):
       screen.blit(self.image, [x1, y1])

然后，在while循环之前，您可以像这样初始化player1对象：player1 = Player1(x1, y1)。

摆脱player1 函数，在您以前调用player1的地方，调用方法 player1.draw(x1, y1)。 / p>

精灵未出现在pygame中

1 个答案: