每当我尝试对其进行编译时,输出均为0。不知道为什么,但是请任何人帮助。
public static void main(String[] args) {
int array1[ ] = {1,2,3};
int array2[ ] = {10,9,8};
int[] c = new int[array1.length];
for(int i = 0; i<array1.length ; i++){
c[i] = array1[i] + array2[i];
System.out.println(ans);
}
}
答案 0 :(得分:1)
错了:
ans
从未定义。c
数组求和,但从不打印它们。这是您应该做的:
public static void main(String[] args) {
int array1[ ] = {1,2,3};
int array2[ ] = {10,9,8};
int[] c = new int[array1.length];
int sumOfAll = 0;
for(int i = 0; i<array1.length ; i++){
c[i] = array1[i] + array2[i];
sumOfAll += c[i];
// if you just want the sum of each index.
System.out.println("Sum each: " + c[i]);
}
// if you want to sum the total of array in c
System.out.println("Sum of all: " + sumOfAll);
}
答案 1 :(得分:0)
您可以将数组元素迭代到单独的循环中,将每个数字求和成一个变量,然后打印出来,就像这样:
public class SumArray {
public static void main(String[] args) {
int array1[ ] = {1,2,3};
int array2[ ] = {10,10,10,10};
int sum = 0;
for (int i : array2) {
sum += i;
}
for (int i : array1) {
sum += i;
}
System.out.println("result: " + sum);
}
}
输出:
result: 46
或带有for和临时变量:
public class SumArray {
public static void main(String[] args) {
int array1[ ] = {1,2,3};
int array2[ ] = {10,10,10,10};
int sum = 0;
for (int i = 0; i < array2.length; i++) {
sum += array2[i];
}
for (int i = 0; i < array1.length; i++) {
sum += array1[i];
}
System.out.println("result: " + sum);
}
}
答案 2 :(得分:0)
public static void main(String[] args) {
int array1[ ] = {1,2,3};
int array2[ ] = {10,9,8};
int[] c = new int[array1.length];
for(int i = 0; i<array1.length ; i++){
c[i] = array1[i] + array2[i];
System.out.println(c[i]);
}
}