Question

我有很多字典。

>[{"name": "John",
"address": 
{"home": "addr1", 
"work": "add2"}
},
{"name": "Anu",
"address": {"home": "addr1", 
"work": "add2"}
}]

我将其保存为用户默认值-

let personData1 = [“名称”：“约翰”，“地址”：{“家庭”：“ addr1”，“工作”：“ add2”}] as [String：Any] let personData2 = [“名称”：“ Anu”，“地址”：{“ home”：“ addr1”，“ work”：“ add2”}] as [String：Any]

var persons = [personsData, personsData1]
UserDefaults.standard.set(forKey: "persons")

以另一种方法检索它，并根据名称对其进行过滤。让名称=“ 约翰”

遇到错误

无法使用类型为（（（Any？）-> Bool）'的参数列表调用'filter'

这是代码：-

func test () {

    let personData1 = ["name": "John", "addresses": ["home":"addr1", "work": "addr2"]] as [String : Any]
    let personData2 = ["name": "And", "addresses":  ["home":"addr1", "work": "addr2"]] as [String : Any]

    let persons = [personData1, personData2]
    (UserDefaults.standard.set(persons, forKey: "persons")

    print("Saved ----\(UserDefaults.standard.value(forKey: "persons"))")

    if let savedPersons = UserDefaults.standard.value(forKey: "persons") {
        let namePredicate = NSPredicate(format: "name like %@", name);

        var filteredArray: [[String:Any]] = savedPersons.filter { namePredicate.evaluate(with: $0) }

        print("names = \(filteredArray)")
    }
}

如果我尝试这样过滤-

let filteredArray = savedBrs.filter { $0["name"] == name }

遇到其他错误-

“任何”类型的值没有成员“过滤器”

Answer 1

使用NSPredicate

let arr = [["name":"Rego","address":["one":"peek","two":"geelo"]],["name":"pppp","address":["one":"peek","two":"geelo"]]]

let neededName = "Rego"

let pre = NSPredicate(format: "name == %@",neededName)

let result = arr.filter { pre.evaluate(with:$0) } 

print(result)

没有NSPredicate

let result = arr.filter { $0["name"] as? String  == neededName }

使用谓词的字典过滤器数组-swift3

1 个答案: