Question

大家好，我有一个字典数组，你能告诉我如何根据字典键过滤这些数据。

DXGI_FORMAT_R1_UNORM

我想要实现的目标，每当我在搜索栏中输入任何内容时，它都会检查mall_name键并返回数组中的匹配值。

谢谢和问候

Answer 1

这将为您提供所需的输出

目标 - C

NSArray *filteredData = [yourArrayContainingDictionary filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", searchText]];

<强>夫特

let filteredData = yourArrayContainingDictionary.filter{
    let string = $0["mall_name"] as! String

    return string.hasPrefix("searchText")
}

希望这可以帮助你：）

Answer 2

试试这个。（谓词就像SQL查询一样）

对象C

 NSArray *filterArray = [sourceArray filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", searchText]];

<强>夫特

var filterArray: [Any] = sourceArray.filter { NSPredicate(format: "(mall_name contains[c] %@)", searchText).evaluate(with: $0) }

它将返回其名称包含搜索字符串的条目。

Answer 3

使用此解决方案

NSArray *filtered = [yourArrayOfDictionary filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name contains[c] %@)", <your search text from search bar>]];

Answer 4

NSArray *filtered = [arrName filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_name == %@)", requiredMailName]];

Answer 5

 NSArray *filtered = [array_with_dict filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_id == %@)", wantedMallID]];

Answer 6

以下是我使用谓词和经典版本的2个版本：

let dict = [
    [
        "mall_id": 1,
        "mall_name": "Amrita Shopping Complex"
    ],
    [
        "mall_id": 2,
        "mall_name": "Ashoka Market"
    ] ]

// Example using Predicate

let mallNamePredicate = NSPredicate(format: "mall_name contains %@", "Ashoka")
let filteredWithPredicate = (dict as NSArray).filtered(using: mallNamePredicate)

// Classical filter example 
let filtered = dict.filter { pair in
    guard let mallName = pair["mall_name"] as? String else { return false }
    return mallName.hasPrefix("Ashoka")
}

Answer 7

这样做的更好的方法就像是

let mallArray  = [
    [
        "mall_id": "M0550",
        "mall_name": "Amrita Shopping Complex"
    ],
    [
        "mall_id": "M0509",
        "mall_name": "Ashoka Market"
    ]
]

func isMatching(_ searchText: String) -> [[String: Any]] {
    let filteredArray = mallArray.filter {
        return $0["mall_name"]!.contains(searchText)
    }
    return filteredArray
}

let malls = isMatching("Ashoka")
print(malls)

Answer 8

这会为您提供一系列仅包含requiredMallID

的词典

 NSArray *filtered = [array_with_dict filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_id == %@)", requiredMallID]];

例如，

NSArray *filtered = [array_with_dict filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"(mall_id == %@)", "M0550"]];

给你

    (
        {
        "mall_id" = M0550;
        "mall_name" = "Amrita Shopping Complex";
    } 
)

使用谓词iOS SDK从Dictionary数组中过滤数据

8 个答案: