Question

即使输入“ exit”或num，程序也不会中断while循环。在函数的底部，我尝试使用guess == num进行检查，然后返回true。函数最底层的代码是此函数的基本结构，并且该代码可以正常工作。不打破while循环的问题是否与函数中的两个for循环有关？谢谢。

def cowsAndBulls():  
    guess = ''  
    num = str(random.randint(1000, 9999))

    while guess != num or guess != 'exit':    
        guess = input('Please enter a guess for a 4-digit number (\'exit\' to leave): ')
        numL = [digit for digit in num]
        guessL = [digit for digit in guess]
        cow = 0
        bull = 0

        for digit in guessL:
            if digit in numL and guessL.index(digit) == numL.index(digit):
                cow = cow + 1
                guessL[guessL.index(digit)] = 'G'
                numL[numL.index(digit)] = 'N'
        for digit in guessL: 
            if digit in numL and guessL.index(digit) != numL.index(digit):
                bull = bull + 1
                guessL[guessL.index(digit)] = 'G'
                numL[numL.index(digit)] = 'N'

        print(num)
        print('Number of cows: ' + str(cow))
        print('Number of bulls: ' + str(bull))
        print(guess == num) 

cowsAndBulls()




guess = ''
num = str(random.randint(0,5))
while guess != num:
    guess = input()
    print(num)

Answer 1

之所以没有结束，是因为除非两个都为假，否则while循环就可以满足了。这行是您麻烦的出处：

while guess != num or guess != 'exit':

如果guess == 'exit'，将发生以下情况：

while False or True:

因为False or True返回True，所以循环将继续运行。为了解决这个问题，我将使用一个变量来保持游戏的运行，并在您想结束游戏时将其设置为false。

while running:

然后在循环内，如果guess =='exit'或num，则将运行设置为False，程序将结束。

Answer 2

import random

def cowsAndBulls():  
    guess = ''  
    num = str(random.randint(1000, 9999))

    while guess != num and guess != 'exit':    
        guess = input('Please enter a guess for a 4-digit number (\'exit\' to leave): ')
        numL = [digit for digit in num]
        guessL = [digit for digit in guess]
        cow = 0
        bull = 0

        for digit in guessL:
            if digit in numL and guessL.index(digit) == numL.index(digit):
                cow = cow + 1
                guessL[guessL.index(digit)] = 'G'
                numL[numL.index(digit)] = 'N'
        for digit in guessL: 
            if digit in numL and guessL.index(digit) != numL.index(digit):
                bull = bull + 1
                guessL[guessL.index(digit)] = 'G'
                numL[numL.index(digit)] = 'N'

        print(num)
        print('Number of cows: ' + str(cow))
        print('Number of bulls: ' + str(bull))
        print(guess == num) 

cowsAndBulls()

将您的or更改为and。

Answer 3

我正在处理您的代码，发现错误，将您的while循环从和或更改为和

while guess != num or guess != 'exit':

到

while guess != num and guess != 'exit':

一旦键入exit，将使循环停止。

祝你好运！

满足条件，但程序不会中断while循环

3 个答案: