while (choice != 7) {
System.out.println("--- Mathematical Calculator ---");
System.out.println("");
System.out.println("Pick an operation from the list - Use nos. 1 to 7");
System.out.println("1) Multiplication");
System.out.println("2) Division");
System.out.println("3) Addition");
System.out.println("4) Subtraction");
System.out.println("5) Find the area of a regular object");
System.out.println("6) Find the volume of a regular object");
System.out.println("7) Exit");
choice = userInput.nextInt();
switch (choice) {
case 1: {
System.out.println("");
System.out.println("You have chosen multiplication");
System.out.println("Enter a number");
double num1 = userInput.nextDouble();
System.out.println("Enter another number");
double num2 = userInput.nextDouble();
double num3 = num1 * num2;
System.out.println(num1 + " * " + num2 + " = " + num3);
num1 = num3;
while (choice2 != 5 || choice2 != 6) {
System.out.println(""); System.out.println("");
System.out.println("If you would like to build on the answer obtained - pick an operation from the list - Use nos. 1 to 4");
System.out.println("Else press 5 to return to the main menu");
System.out.println("1) Multiplication");
System.out.println("2) Division");
System.out.println("3) Addition");
System.out.println("4) Subtraction");
System.out.println("5) Start new calculation");
System.out.println("6) Exit");
choice2 = userInput.nextInt();
switch (choice2) {
case 1:
{
System.out.println("Enter number");
num2 = userInput.nextDouble();
num3 = num1 * num2;
System.out.println(num1 + " * " + num2 + " = " + num3);
num1 = num3;
break;
}
case 2:
{
System.out.println("Enter number");
num2 = userInput.nextDouble();
num3 = num1 / num2;
System.out.println(num1 + " / " + num2 + " = " + num3);
num1 = num3;
reak;
}
case 3:
{
System.out.println("Enter number");
num2 = userInput.nextDouble();
num3 = num1 + num2;
System.out.println(num1 + " + " + num2 + " = " + num3);
num1 = num3;
break;
}
case 4:
{
System.out.println("Enter number");
num2 = userInput.nextDouble();
num3 = num1 - num2;
System.out.println(num1 + " - " + num2 + " = " + num3);
num1 = num3;
break;
}
case 5: choice = 0; break;
case 6: choice = 7; break;
default: System.out.println("Invalid choice");
}
choice2 = 0;
}
break;
}
我发布了一小段代码。我的问题是,当我在第二个查询(choice2
)中输入5或6时,我的程序继续循环而不是退出循环并返回主菜单/终止程序。
希望得到一些关于我做错事的反馈。
答案 0 :(得分:6)
你的while (choice2 != 5 || choice2 != 6)
错了,因为它总是会导致真的。如果choice2为5,则第二个子句为真。
更不用说你总是在循环结束时将choice2设置为0,所以即使你用||
替换&&
,循环也会永远继续。
答案 1 :(得分:3)
条件choice2 != 5 || choice2 != 6
始终为真,因为没有数字同时等于5和6。
如果您想在输入5或6时退出循环,请改用&&
:
while (choice2 != 5 && choice2 != 6)
确保在继续循环的下一次迭代之前设置choice2
。
请注意,您可以使用带标签的break结构从switch
语句中突破循环:
calc: // Label the loop for using labeled break
while (true) {
...
switch(...) {
case 1:
break; // This will exit the switch
...
case 6: break calc; // This will exit the loop
}
}