在暂停和重新创建活动后,如何停止附加的活动?

时间:2018-08-08 13:22:00

标签: android alertdialog android-dialogfragment

我正在研究项目,该项目仅通过用户名和密码进行验证。

我在使用DialogFragments和AlertDialog方面取得了一些进展。在mainactivity上启动应用程序后,出现AlertDialog并询问用户名和密码。 我必须设置Alertdialog的setCanceledOnTouchOutside(false)和DialogFragment的setCancelable(false),因为我不希望用户通过按下android的后退按钮来关闭它。

问题是,在成功登录后以编程方式将其关闭后,如果活动变得不可见并且再次可见,则Alertdialog的OnShowListener会调用,再次显示此AlertDialog。

我可以通过某种方式从活动中“分离”此AlertDialog吗?解锁屏幕并恢复活动后,也会弹出此弹出窗口,这非常烦人...

这是您感兴趣的代码:

MainActivity

public class MainActivity extends AppCompatActivity implements NoticeDialogFragment.NoticeDialogListener {


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    if(GlobalInformations.getInstance().getUsername()==null){
        shownoticeDialog();
    }
}

public void shownoticeDialog(){
    DialogFragment dialogFragment = new NoticeDialogFragment();
    dialogFragment.show(getFragmentManager(), "NoticeDialogFragment");
}

@Override
public void onDismiss(DialogFragment dialog) {
   //set the username on a TextView instance, etc...
}

NoticeDialogFragment扩展DialogFragment

public class NoticeDialogFragment extends DialogFragment {

public interface NoticeDialogListener{
    public void onDialogPositiveClick(DialogFragment dialog);
    public void onDialogNegativeClick(DialogFragment dialog);
    public void onDismiss(DialogFragment dialog);
}

NoticeDialogListener mListener;
static Activity activity = null;
//static String username;

@Override
public void onAttach(Context context) {
    super.onAttach(context);
    try{
        activity = (Activity) context;
        mListener = (NoticeDialogListener) activity;

    } catch (ClassCastException e){
        throw new ClassCastException(activity.toString() + "must implement NoticeDialogListener");
    }
}

@Override
public Dialog onCreateDialog(Bundle savedInstanceState) {

    LayoutInflater inflater = getActivity().getLayoutInflater();
    View view = inflater.inflate(R.layout.dialog_signin, null);

    final AutoCompleteTextView actv_username = (AutoCompleteTextView) view.findViewById(R.id.username);
    final EditText password = (EditText) view.findViewById(R.id.password);

    getavailableusernames(actv_username);

    final AlertDialog dialog = new AlertDialog.Builder(new ContextThemeWrapper(getContext(), R.style.AlertDialogCustom))
            .setView(view)
            .setTitle("Login")
            .setPositiveButton("OK", null)
            //.setNegativeButton("Cancel", null)
            .create();

    dialog.setOnShowListener(new DialogInterface.OnShowListener() {
        @Override
        public void onShow(DialogInterface dialogInterface) {
            final Button button =((AlertDialog) dialog).getButton(AlertDialog.BUTTON_POSITIVE);
            button.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    String passw = password.getText().toString();
                    String user = actv_username.getText().toString();
                    try{
                        if(user.length()<4 || passw.length()<4){
                            Toast.makeText(getContext(), "Username/password too short", Toast.LENGTH_SHORT).show();
                            dialog.show();
                        }
                        else {
                            //login to account, if success dismiss.
                          login(user, passw,dialog);
                        }


                    } catch(Exception e){

                    }
                    //  dialog.dismiss();
                }
            });
        }
    });
    dialog.setCanceledOnTouchOutside(false);

    // set the DialogFragment to make the dialog unable to dismiss with back button
    // (because not working if called on the dialog directly)
    this.setCancelable(false);

    return dialog;
}

 public void login(final String username, String password, final AlertDialog dialog){

    boolean login_success = false;
    //query the credentials
    login_success = dosomesqlquery(username, password);

    if(login_success){
         dialog.dismiss();
    }
 }

//passing the handling to activity...
@Override
public void onDismiss(DialogInterface dialog) {
    mListener.onDismiss(NoticeDialogFragment.this);
}

}

感谢您的帮助和耐心。

3 个答案:

答案 0 :(得分:1)

在这种情况下,我最终要连续向办公桌走去。

问题的根源是我叫dialog.dismiss(),它关闭了对话框,但不是对话框片段本身,所以即使对话框从屏幕上消失了也永远不会关闭。将this.dismiss()放置在NoticeDialogFragment的onDismiss或成功登录后的任何其他位置,将使应用程序按其应有的方式运行。

--xmlout

感谢您的时间和回答,因为它们帮助我指出了真正的问题。我将根据您的建议修改代码。

答案 1 :(得分:0)

设置活动进入后台时的值

@Override
protected void onSaveInstanceState(Bundle outState) {
    outState.putBoolean("authUser", GlobalInformations.getInstance().getUsername()==null)
}

并在回来时阅读

@Override
protected void onCreate(Bundle savedInstanceState) {
    if(savedInstanceState != null && savedInstanceState.containsKey("authUser")) {
         boolean authUser = savedInstanceState.getBoolean("authUser", false);
         if(authUser) {
             //show or don't show dialog
         }
    }
}

答案 2 :(得分:0)

一种更简单的方法是通过两个步骤在您的活动中使用静态变量。

  1. 声明全局静态布尔

    private static boolean session = false;

  2. 检查布尔值是否已更改,如果没有更改,则在显示对话框时将布尔值设置为true

    public void shownoticeDialog(){ 如果(会话)返回; DialogFragment dialogFragment =新的NoticeDialogFragment(); dialogFragment.show(getFragmentManager(),“ NoticeDialogFragment”); session = true; }