Question

嘿，我的问题很简单：我有这个请求：

->prepare("SELECT
    CONCAT(YEAR(`p`.`created_account`), '-', MONTH(`p`.`created_account`)) AS `month` 
    FROM
   `profile` AS `p` 
    GROUP BY
    YEAR(`p`.`created_account`), MONTH(`p`.`created_account`)");

我在mysql 5中可以正常工作，但是我升级到mysql 8并知道我有此错误：

object（Doctrine \ DBAL \ Exception \ SyntaxErrorException）＃707（8）{[“” driverException“：” Doctrine \ DBAL \ Exception \ DriverException“：private] =>对象（Doctrine \ DBAL \ Driver \ PDOException）＃766 （10）{[“” ErrorCode“：” Doctrine \ DBAL \ Driver \ PDOException“：private] => int（1064）[” sqlState“：” Doctrine \ DBAL \ Driver \ PDOException“：private] =>字符串（5） “ 42000” [“消息”：受保护的] =>字符串（282）“ SQLSTATE [42000]：语法错误或访问冲突：1064您的SQL语法有错误；请查看与您的MySQL服务器版本相对应的手册在'FROM profile AS p GROUP BY YEAR（p。created_account），MONTH（p。'created_a'的第1行附近使用正确的语法” [“ string”：“ Exception”：private] =>字符串（0）“” [“”“：protected] =>字符串（5）” 42000“ [” file“：protected] =>字符串（92）

如果可以的话，我可以同时在两个版本中使用它：

->prepare("SELECT COUNT(`p`.`id`) AS `total` FROM `profile` AS `p` GROUP BY YEAR(`p`.`created_account`), MONTH(`p`.`created_account`)");

当我删除该工作组但不按：/分组时，我有：

array（9）{[0] => array（1）{[“ month”] => string（6）“ 2018-6”} [1] => array（1）{[“ month”] =>字符串（6）“ 2018-6”} [2] =>数组（1）{[“”“] =>字符串（6）” 2018-7“} [3] =>数组（1）{[ “ month”] => string（6）“ 2018-8”} [4] => array（1）{[“” month“] => string（6）” 2018-8“} [5] => array（ 1）{[“”“] =>字符串（6）” 2018-8“} [6] =>数组（1）{[”“”“ =>字符串（6）” 2018-8“} [7] => array（1）{[“”“] =>字符串（6）” 2018-8“} [8] => array（1）{[”“”] => string（6）“ 2018-8” }

那么我该怎么做才能不重复当月？感谢所有尝试回答的人：p

Answer 1

似乎您缺少CONCAT()的大括号你可以尝试：

SELECT CONCAT(YEAR(`p`.`created_account`), '-', MONTH(`p`.`created_account`)) AS `month` FROM `profile` AS `p` GROUP BY YEAR(`p`.`created_account`), MONTH(`p`.`created_account`)

Answer 2

好吧，我发现对于有相同问题的人来说，这样做是这样的：（似乎mysql v8不允许按年份或月份进行分组，所以就这样做：）

->prepare("SELECT DISTINCT CONCAT(YEAR(`p`.`created_account`), '-', MONTH(`p`.`created_account`)) AS `month` FROM `profile` AS `p` GROUP BY (`created_account`)");

SQL请求错误语法

2 个答案: