PHP MySQL请求错误：解析错误：语法错误，意外'％'

Question

我对我的PHP代码有疑问：

$result = mysqli_query($con,"UPDATE operasyonkayitlari SET tarihgun=FROM_UNIXTIME(UNIX_TIMESTAMP(NOW())-28800, "%Y.%m.%d"), tezgah='".$_REQUEST['tezgah']."', operatoradi='".$_REQUEST['operator']."', ayarepoch=UNIX_TIMESTAMP(NOW()), durum='AYARDA' where isemri='".$_REQUEST['isemri']."' and operasyonno='".$_REQUEST['operasyonno']."'");

仔细看看：

FROM_UNIXTIME(UNIX_TIMESTAMP(NOW())-28800, "%Y.%m.%d")

带有％符号的字符会给我这个语法错误：

Parse error: syntax error, unexpected '%' in C:\wamp\www\ayarabasla.php on line 4

我是如何使用％符号编写查询的？

Answer 1

语法高亮显示器显示您的错误。这是一个报价问题。逃避你的内在双引号：

$result = mysqli_query($con,"UPDATE operasyonkayitlari SET tarihgun=FROM_UNIXTIME(UNIX_TIMESTAMP(NOW())-28800, \"%Y.%m.%d\"), tezgah='".$_REQUEST['tezgah']."', operatoradi='".$_REQUEST['operator']."', ayarepoch=UNIX_TIMESTAMP(NOW()), durum='AYARDA' where isemri='".$_REQUEST['isemri']."' and operasyonno='".$_REQUEST['operasyonno']."'");

您也可以使用单引号：

$result = mysqli_query($con,"UPDATE operasyonkayitlari SET tarihgun=FROM_UNIXTIME(UNIX_TIMESTAMP(NOW())-28800, '%Y.%m.%d'), tezgah='".$_REQUEST['tezgah']."', operatoradi='".$_REQUEST['operator']."', ayarepoch=UNIX_TIMESTAMP(NOW()), durum='AYARDA' where isemri='".$_REQUEST['isemri']."' and operasyonno='".$_REQUEST['operasyonno']."'");