Question

我有2种表格，我们将其称为表格A和B。在表单A中，我有一个按钮（空白按钮），单击该按钮时它将重定向到带有参数的表单B，并且该参数将注入到表单B的数据源中。我无法检索到表单B的数据源，但始终返回null。

[FormControlEventHandler(formControlStr(htVehicleListPage, FormCommandButtonControl1), FormControlEventType::Clicked)]
    public static void FormCommandButtonControl1_OnClicked(FormControl sender, FormControlEventArgs e)
    {
        FormDataSource htVehicleTable= sender.formRun().dataSource(formDataSourceStr(htVehicleListPage,htVehicleTable));
        htVehicleTable record=htVehicleTable.cursor();
        info(int2Str(record.htVehicleID)); //result: some legit ID.
        Args argsObj=new Args();
        argsObj.name(formStr(htVehicleMaintenanceDetails));
        FormRun formRunObj=new FormRun(argsObj);
        FormDataSource openningFormDataSource =formRunObj.dataSource(formDataSourceStr(htVehicleMaintenanceDetails,htVehicleMaintenance)); //result: openningFormDataSource is null, however, formRunObj is not null.
        Query queryObj=new Query();
        openningFormDataSource.query(queryObj);
        QueryBuildDataSource queryBuildDataSourceObj=queryObj.addDataSource(tableNum(htVehicleMaintenance));
        queryBuildDataSourceObj.addRange(fieldNum(htVehicleMaintenance,htVehicleID)).value(strFmt("htVehicleMaintenance.htVehicleID=%1",record.htVehicleID));
        formRunObj.init();
        formRunObj.run(); //if we inorge the null error it will show a form here
        formRunObj.wait();
    }

Answer 1

FormRun只是...它是正在运行的表单对象。您的openningFormDataSource将为空，仅仅是因为您在formRunObj.init();之前调用了该表单，而表单尚未运行。

先行Form.init()，然后再行Form...Datasource.init()，然后再行Form.run()。

将您的formRunObj.init()移至更高位置，然后重试。

尝试从FormRun检索数据源时获取null

1 个答案: