Question

这是代码，但是导出的xml格式错误。

import xml.etree.ElementTree as ET
import os

sampleXML = """<?xml version="1.0" encoding="ASCII"?>
    <Metadata version="1.0">
        <CODE_OK>510</CODE_OK>
        <DeliveryDate>13/08/2018</DeliveryDate>
    </Metadata>
    """

tree = ET.ElementTree(ET.fromstring(sampleXML))
for folder in os.listdir("YourPath"):         #Iterate the dir
    tree.find("CODE_OK").text = folder        #Update dir name in XML
    tree.write(open(os.path.join(r"Path", folder, "newxml.xml"), "wb")) #Write to XML

如何使导出的xml以正常格式显示？

Answer 1

我在docs中发现，xml模块具有文档对象模型接口的实现。我提供了一个简单的示例

from xml.dom.minidom import parseString

example = parseString(sampleXML) # your string

# write to file
with open('file.xml', 'w') as file:
    example.writexml(file, indent='\n', addindent=' ')

输出：

<?xml version="1.0" ?>
<Metadata version="1.0">


 <CODE_OK>510</CODE_OK>


 <DeliveryDate>13/08/2018</DeliveryDate>


</Metadata>

更新

您也可以这样写

example = parseString(sampleXML).toprettyxml()
with open('file.xml', 'w') as file:
    file.write(example)

输出：

<?xml version="1.0" ?>
<Metadata version="1.0">


    <CODE_OK>510</CODE_OK>


    <DeliveryDate>13/08/2018</DeliveryDate>


</Metadata>

更新2

我复制了您所有的代码，仅从此site中添加了indent。对我来说工作正常

import xml.etree.ElementTree as ET
import os

sampleXML = "your xml"
tree = ET.ElementTree(ET.fromstring(sampleXML))

indent(tree.getroot()) # this I add

for folder in os.listdir(path):
    tree.find("CODE_OK").text = folder
    tree.write(open(os.path.join(path, folder, "newxml.xml"), "wb"))

导出的xml格式不正确，但是显示为一行？

1 个答案: