Question

<list>
<interfaceReachability  type="Critical" count="345" httpLink="searchLradIfAction_pageId?isAscending=true&operation=monitor&searchApByType=AllTypes&searchRadioTypeallRadios=true&searchApType=homePage&severity=1" />
<interfaceReachability  type="No Alarms" count="6216" httpLink="searchLradIfAction_pageId?isAscending=true&operation=monitor&searchApByType=AllTypes&searchRadioTypeallRadios=true&searchApType=homePage&severity=5" />
<interfaceReachability  type="Minor" count="145" httpLink="searchLradIfAction_pageId?isAscending=true&operation=monitor&searchApByType=AllTypes&searchRadioTypeallRadios=true&searchApType=homePage&severity=3" />
</list>

我想将此 XML转换为Json 。由于此XML格式不正确且元素包含'＆amp;'和'？' Org.json没有转换它。任何帮助将非常感激。我真的卡在这里。我试过了

org.json.JSONObject xmlJSONObj = XML.toJSONObject(TEST_XML_STRING);
                 String jsonPrettyPrintString = xmlJSONObj.toString(PRETTY_PRINT_INDENT_FACTOR);
                System.out.println(jsonPrettyPrintString);

但没有运气。再次感谢

Answer 1

您必须用'&'实体替换&的出现次数，否则它不是有效的XML。

没有很好地格式化-XML到Json转换

1 个答案: