SQL按字符串+整数的顺序

Question

如何按字符串末尾的ID排序？

例如，我想按末尾的数字对这些字符串进行排序（在RSPP之后）：

RSPP891
RSPP896
RSPP897
RSPP898
RSPP899
RSPP900
RSPP901
RSPP902
RSPP903
RSPP904
RSPP730
RSPP731
RSPP1380
RSPP733
RSPP734

我读了一些有关子字符串的知识，所以我尝试了该查询，但没有成功。

SELECT `RsppTags` FROM Table WHERE ConnectionID = 15202  
ORDER BY
SUBSTR(RsppTags FROM 4 FOR LENGTH(RsppTags)-1),
CAST(SUBSTR(RsppTags FROM 1) AS UNSIGNED)

是否可以获取此数据ORDER BY ASC？

Answer 1

SELECT RsppTags FROM Table WHERE ConnectionID = 15202 ORDER BY CAST(SUBSTR(RsppTags FROM 5) AS UNSIGNED)

默认情况下，MYSQL提供ASC排序。

尝试上述查询。 它将为您提供帮助。

Answer 2

尝试：

ORDER BY CAST(SUBSTR(RsppTags FROM 5) AS UNSIGNED) ASC

Sample SQL Fiddle showing the result

Answer 3

order by SUBSTR(RsppTags, 5) + 0

Answer 4

尝试

SELECT `RsppTags` FROM Table WHERE ConnectionID = 15202  
ORDER BY CAST(SUBSTR(RsppTags, 5) AS UNSIGNED) ASC;

Answer 5

SELECT `RsppTags` 
FROM Table WHERE ConnectionID = 15202  
ORDER BY
SUBSTR(RsppTags,1,4), 
CAST(SUBSTR(RsppTags,5) AS UNSIGNED);