Question

需要根据日期和序列号降序来订购ID

ID是一些串联字符串值的组合 BM-6至8位数字代码-日期（DDMMYY）-序列号（01-99）

Create table #tempcheck (id varchar(50))
Insert into #tempcheck values('BM72220901021904')
Insert into #tempcheck values('BM72220901021906')
Insert into #tempcheck values('BM72220931011901')
Insert into #tempcheck values('BM72220931011903')
Select * from  #tempcheck order by id desc

id  
BM72220901021906  
BM72220901021904  
BM72220931011903  
BM72220931011901

Answer 1

尝试一下：

SELECT 
  *
from #tmpcheck
order by
  CONVERT(DATE, SUBSTRING(id, 9, 6)) AS date desc,
  CONVERT(int, RIGHT(id,2))  seq desc

问题在于日期之前的部分可以是可变长度

SELECT 
  *
from #tmpcheck
order by
  CONVERT(DATE, SUBSTRING(RIGHT(id, 8), 1, 6)) AS date desc,
  CONVERT(int, RIGHT(id,2))  seq desc

Answer 2

您可以使用以下解决方案：

SELECT CONVERT(DATE, SUBSTRING(id, LEN(id) - 5, 2) + '/' + SUBSTRING(id, LEN(id) - 7, 2) + '/' + SUBSTRING(id, LEN(id) - 3, 2), 1) AS datevalue, RIGHT(id, 2) AS seq 
FROM #tempcheck 
ORDER BY CONVERT(DATE, SUBSTRING(id, LEN(id) - 5, 2) + '/' + SUBSTRING(id, LEN(id) - 7, 2) + '/' + SUBSTRING(id, LEN(id) - 3, 2), 1) DESC, RIGHT(id, 2) DESC

demo on dbfiddle.uk

Answer 3

此解决方案应该可以做到。它仅使用字符串操作（不进行数据类型转换），并且应该相当快。

SELECT *
FROM #tempcheck 
ORDER BY Left(Right(id, 4), 2) + Left(Right(id, 6), 2)
       + Left(Right(id, 8), 2) + Right(id, 2) DESC

它从字符串的后端开始计算字符，因此日期之前的可变长度（6-8）代码无关紧要。

按字符串排序

3 个答案: