Question

我对oracle完全陌生。我有一张桌子，上面存储着工作日。我想在满足输入条件的情况下得到第5个工作日（第5行）。例如，请考虑下表

 BUSINESS DAY
8/06/2004 12:00:00 AM
8/07/2004 12:00:00 AM
8/08/2004 12:00:00 AM
8/09/2004 12:00:00 AM
8/10/2004 12:00:00 AM
8/13/2004 12:00:00 AM
8/14/2004 12:00:00 AM
8/15/2004 12:00:00 AM
8/16/2004 12:00:00 AM

在这里，我的输入日期为2004年8月8日12:00:00 AM，我的输出应为2004年8月15日12:00:00 AM。请帮助构建查询。请注意，根据要求，我可能还需要过去的日期。

我还提到了其他栈问题和答案。但是似乎它们都不符合我的问题。

Answer 1

演示表：

create table business_days (busday) as
    select date '2004-08-06' from dual union
    select date '2004-08-07' from dual union
    select date '2004-08-08' from dual union
    select date '2004-08-09' from dual union
    select date '2004-08-10' from dual union
    select date '2004-08-13' from dual union
    select date '2004-08-14' from dual union
    select date '2004-08-15' from dual union
    select date '2004-08-16' from dual;

一种方法：

select busday, t_plus_5
from   ( select busday
              , lead(busday,5) over (order by busday) as t_plus_5
         from   business_days
         where  busday >= date '2004-08-08' )
where   busday = date '2004-08-08';

或者这（需要Oracle 12.1或更高版本）：

select busday
     , ( select d5.busday from business_days d5
         where  d5.busday >= d1.busday
         order by busday
         offset 5 rows fetch first row only ) as t_plus_5
from   business_days d1
where  busday = date '2004-08-08';

Answer 2

这是一个选择：订购业务日期（使用ROW_NUMBER分析函数），然后对其应用简单的算术运算（即加5天，或减去一些天）：

SQL> with test (busday) as
  2    (select date '2004-08-06' from dual union
  3     select date '2004-08-07' from dual union
  4     select date '2004-08-08' from dual union
  5     select date '2004-08-09' from dual union
  6     select date '2004-08-10' from dual union
  7     select date '2004-08-13' from dual union
  8     select date '2004-08-14' from dual union
  9     select date '2004-08-15' from dual union
 10     select date '2004-08-16' from dual
 11    ),
 12  inter as
 13    (select busday, row_number() over (order by busday) rn
 14     from test
 15    )
 16  select i.busday
 17  from inter i
 18  where i.rn = (select i1.rn + 5 from inter i1
 19                where i1.busday = date '&par_busday'
 20               );
Enter value for par_busday: 2004-08-08

BUSDAY
----------
2004-08-15

SQL>

从满足输入条件的位置选择第n行-Oracle数据库-SQLdbx

2 个答案: