希望这是一个非常简单的问题。我有一个抄本,试图将每个发言人分成几部分。我当前拥有的代码是;
text = '''
Speaker 1: hello there
this is some text.
Speaker 2: hello there,
this is also some text.
'''
a = text.split('\nSpeaker')
这会按照我想要的方式拆分文本,但是我错过了第二个发音中的“扬声器”标识符。我需要保留此信息以用于识别。具体来说,我想要获得的结果类似于以下内容;
['Speaker 1: hello there\n\nI am checking to see if this works. \n', ' Speaker2:
Hopefully it will, \n\nit seems pretty straightforward.\n']
欢迎提出任何建议
谢谢
答案 0 :(得分:2)
re.split
在多行模式下,匹配\n
(换行符),且零宽度正向超前以匹配Speaker
((?=Speaker)
):
re.split(r'\n(?=Speaker)', text, flags=re.MULTILINE)
示例:
In [228]: text = '''Speaker 1: hello there
...:
...: this is some text.
...:
...: Speaker 2: hello there,
...:
...: this is also some text.
...: '''
In [229]: re.split(r'\n(?=Speaker)', text, flags=re.MULTILINE)
Out[229]:
['Speaker 1: hello there\n\nthis is some text. \n',
'Speaker 2: hello there, \n\nthis is also some text.\n']
答案 1 :(得分:1)
非正则表达式解决方案:
['Speaker' + substr for substr in text.split('Speaker')[1:]]
输出
['Speaker 1: hello there\n\nthis is some text. \n\n',
'Speaker 2: hello there, \n\nthis is also some text.\n']