假设我们有一个包含以下数据的数据集:
timestamp,col1
1533286270,1
1533286271,2
1533286272,3
1533286273,4
1533286274,5
我想获取col1
中col1_prev
之前的值,以便能够进行比较。结果应与pandas.shift(-1)
相同。
如何通过普通的SQL查询实现此功能?
查询结果应如下所示:
timestamp,col1,col1_prev
1533286270,1,NULL
1533286271,2,1
1533286272,3,2
1533286273,4,3
1533286274,5,4
答案 0 :(得分:4)
使用lag()
函数是一种方法:
WITH
input AS (
SELECT
1533286270 AS timestamp,
1 AS col1
UNION ALL
SELECT
1533286271 AS timestamp,
2 AS col1
UNION ALL
SELECT
1533286272 AS timestamp,
3 AS col1
UNION ALL
SELECT
1533286273 AS timestamp,
4 AS col1
UNION ALL
SELECT
1533286274 AS timestamp,
5 AS col1 )
SELECT
timestamp,
col1,
LAG(col1) OVER(ORDER BY col1) AS col1_prev
FROM
input