Question

试图用今天的日期减去created_date列填充一列，但出现以下错误：TypeError：-：'str'和'str'的不支持的操作数类型

import datetime
now = datetime.date.today()
today = '{0:%m/%d/%Y}'.format(now).format(now)
today
data['Aging'] = today
data['Aging'] = data['Aging'].sub(data['Created_Date'], axis=0)

TypeError：--'str'和'str'的不受支持的操作数类型

Answer 1

我认为需要减去datetime，因此有必要在date和now列中转换Created_Date，最后将timedelta s转换为天数dt.days：

import datetime
now = datetime.date.today()
today = pd.Timestamp(now)

data['Created_Date'] = pd.to_datetime(data['Created_Date'])
data['Aging'] = today
data['Aging'] = data['Aging'].sub(data['Created_Date'], axis=0).dt.days

解决方案应该简化：

data['Created_Date'] = pd.to_datetime(data['Created_Date'])
data['Aging'] = data['Created_Date'].rsub(today, axis=0).dt.days

Answer 2

也许，请尝试将其作为完整代码：

data['Created_Date'] = pd.to_datetime(data['Created_Date'])
data['Aging'] = pd.to_datetime('now')
data['Aging'] = data['Aging'].sub(data['Created_Date'], axis=0)

您想要什么，也许：

data['Created_Date'] = pd.to_datetime(data['Created_Date'])
data['Aging'] = pd.to_datetime('now').strftime('%m/%d/%Y')
data['Aging'] = data['Aging'].sub(data['Created_Date'], axis=0)

熊猫-Python-如何减去两个不同的日期列

2 个答案: