Question

我正在尝试使用Scrapy和Splash解析此Target search page上的产品名称。我使用Splash发送请求yield SplashRequest(url=i, callback=self.parse, headers = {"User-Agent": ua.chrome})，然后使用parse函数提取product_name：

def parse(self, response):

    print("INSIDE PARSE TARGET")
    for product in response.xpath('//div[@data-test="productGridContainer"]/div[2]/ul/li//div[@data-test="product-card"]'):

        print("in PRODUCT")

        print(product)
        product_name = product.xpath('.//div[@data-test="productCardBody"]/div[@data-test="product-details"]/div[contains(@class,"ProductTitle")]/a[1]/@aria-label').extract_first()
        print("Product name: " + str(product_name))
        print("ratio: " + str(fuzz.partial_ratio(target_name.lower(), product_name.lower())))

        if fuzz.partial_ratio(target_name.lower(), product_name.lower()) > self.max_score:
            self.max_score = fuzz.partial_ratio(target_name.lower(), product_name.lower())
            self.product_page = product.xpath('.//div[@data-test="productCardBody"]/div[@data-test="product-details"]/div[contains(@class,"ProductTitle")]/a[1]/@href').extract_first()
            print("product_page: " + self.product_page)

        print("---------------------------------------")

    print("***********************************")
    print("max_score is: " + str(self.max_score))
    self.product_page = response.urljoin(self.product_page)
    print("FOUND PRODUCT AT PAGE: " + self.product_page)
    yield SplashRequest(url=self.product_page, callback=self.parseProduct, headers = {"User-Agent": ua.chrome})

但是，这就是我所得到的。它永远不会进入for循环，我不明白。

2018-08-01 14:08:04 [scrapy.core.engine] INFO: Spider opened
2018-08-01 14:08:04 [scrapy.extensions.logstats] INFO: Crawled 0 pages (at 0 pages/min), scraped 0 items (at 0 items/min)
2018-08-01 14:08:04 [scrapy.extensions.telnet] DEBUG: Telnet console listening on 127.0.0.1:6044
2018-08-01 14:08:07 [scrapy.core.engine] DEBUG: Crawled (200) <GET https://www.target.com/s?searchTerm=google+home+%2B via http://localhost:8050/render.html> (referer: None)
INSIDE PARSE TARGET
***********************************
max_score is: 0
FOUND PRODUCT AT PAGE: https://www.target.com/s?searchTerm=google+home+%2B
2018-08-01 14:08:07 [scrapy.dupefilters] DEBUG: Filtered duplicate request: <GET https://www.target.com/s?searchTerm=google+home+%2B> - no more duplicates will be shown (see DUPEFILTER_DEBUG to show all duplicates)
2018-08-01 14:08:07 [scrapy.core.engine] INFO: Closing spider (finished)

Answer 1

您的搜寻器中没有循环。如该日志行所示：

调试：已过滤的重复请求：https://www.target.com/s?searchTerm=google+home+%2B>-将不再显示重复项（请参阅DUPEFILTER_DEBUG以显示所有重复项）

您正尝试再次爬网刚刚爬过的页面，而scrapy的dupe过滤器正在过滤掉此请求。

似乎您的self.product_page返回的网址与您相同，而不是新的网址。我对您的代码进行了一些重构，以尝试理解您的问题：

def parse(self, response):
    products = response.xpath('//div[@data-test="productGridContainer"]/div[2]/ul/li//div[@data-test="product-card"]')
    max_score = 0
    target_name = '???'
    product_page = None
    for product in products:
        name = product.xpath('.//div[@data-test="productCardBody"]/div[@data-test="product-details"]/div[contains(@class,"ProductTitle")]/a[1]/@aria-label').extract_first()
        url = product.xpath('.//div[@data-test="productCardBody"]/div[@data-test="product-details"]/div[contains(@class,"ProductTitle")]/a[1]/@href').extract_first()
        if response.urljoin(url) == response.url:
            continue # avoid crawling current page
        ratio = fuzz.partial_ratio(target_name.lower(), name.lower()))
        if ratio > self.max_score:
            max_score = ratio
            product_page = url

    if product_page:
        print(f'max_score: {max_score}')
        print(f'product: {product_page}')
        yield SplashRequest(response.urljoin(product_page), 
                            callback=self.parse_product, 
                            headers = {"User-Agent": ua.chrome})

xpath无法在Scrapy的解析中正确选择HTML

1 个答案: