Question

实际上我不知道如何搜索这个问题，如果是css或php问题。我有一个div打开一个隐藏的div。当我在网站外测试代码时，它工作正常。当我在网站内测试时，我接受了这个。看这里的图片（http://grab.by/H8TW）

代码的完整构造是：

<ol>
<div><div>
<div></div>
<div>
<li>
<div class="lyrics">
<article>
<input type="checkbox" id="read_more" role="button">
<label for="read_more" onclick=""><span>Lyrics</span><span>Hide Lyrics</span></label>
<section></section>    
<section><?php $lyric = get_post_meta(get_the_ID(), '_lyrics', true); echo $lyric; ?>
</section>
</article>
</div>
</div>
</li>
</ol>

CSS

div.lyrics {
position: relative;
top: 10px;
}

article {
    margin-bottom: 3rem;
    position: relative;
    *zoom: 1;
}

article:before, article:after {
    content: "";
    display: block;
}

article:after { clear: both }

article figure {
    float: right;
    width: 32.5%;
}

article section:first-of-type {
    float: left;
    width: 62.5%;
}

article section:last-of-type {
    display: none;
    visibility: hidden;

}

section {
    -webkit-transition: .125s linear;
    -moz-transition: .125s linear;
    -ms-transition: .125s linear;
    -o-transition: .125s linear;
    transition: .125s linear;
}

input[type=checkbox] {
    border: 0;
    clip: rect(0 0 0 0);
    height: 1px;
    width: 1px;
    margin: -1px;
    overflow: hidden;
    padding: 0;
    position: absolute;
}

[for="read_more"] {
    position: absolute;
    bottom: -3rem;
    left: 0;
    width: 100%;
    text-align: center;
    padding: .65rem;
    box-shadow: inset 1px 1px rgba(0, 0, 0, 0.1), inset -1px -1px rgba(0, 0, 0, 0.1);
}

[for="read_more"]:hover {
    background: rgba(0,0,0,.5);
    color: rgb(255,255,255);
}

[for="read_more"] span:last-of-type {
    display: none;
    visibility: hidden;
}

input[type=checkbox]:checked ~ section {
    display: block;
    visibility: visible;
    width: 100%;
}

input[type=checkbox]:checked ~ figure { width: 100% }

input[type=checkbox]:checked ~ [for="read_more"] span:first-of-type {
    display: none;
    visibility: hidden;
}

input[type=checkbox]:checked ~ [for="read_more"] span:last-of-type {
    display: block;
    visibility: visible;
}

感谢您的帮助！

Answer 1

问题的解决方案来自文本编辑器，我在每次休息时使用enter（＆lt; br＆gt;）我想拥有！因此，每个文本行都是一个段落（＆lt; p＆gt;）。

php文本没有正确显示

1 个答案: