我的应用程序中有两个低于RxnsSearchService
和RxnsSearchHitCountService
的HTTP服务。
使用forkJoin
处理两个请求,如下面的代码。
constructor(
private rxnsSearchService: RxnsSearchService,
private rxnsSearchHitCountService: RxnsSearchHitCountService
) { }
const rxnsObservable: Observable<Array<any>> = this.rxnsSearchService.getReactions(this.searchParams, filters);
const headCountObservable: Observable<number> = this.rxnsSearchHitCountService.getHitCount(this.searchParams, filters);
forkJoin([rxnsObservable, headCountObservable]).pipe().subscribe((results) => { //handling results
},
error => {
console.log(error);
});
每当有新请求出现时,我都想取消正在进行的旧请求。谁能帮助我,使它变通?
export class RxnsSearchService {
sub: Subject<any> = new Subject();
constructor(private httpClient: HttpClient) {}
getReactions(params: Params, offset: number, perPage: number, filters: any) {
const body = {
filters: filters,
query: params.query
};
return this.httpClient.post(environment.rxnsSearch, body).pipe(
map((response: Array<any>) => {
return response;
}),
catchError(error => {
console.log(error);
return throwError(error);
})
);
}
}
export class RxnsSearchHitCountService {
constructor(private httpClient: HttpClient) {}
getHitCount(params: Params, filters: any) {
const body = {
filters: filters,
query: params.query,
};
return this.httpClient.post(environment.rxnsSearchHitCount, body).pipe(
map((response: number) => {
return response;
}),
catchError(error => {
console.log(error);
return throwError(error);
})
);
}
}
答案 0 :(得分:2)
我将通过一个简化的示例介绍通用的方法。说我们目前有这个:
public getReactions() {
this.http.get(…)
.subscribe(reactions => this.reactions = reactions);
}
确保取消旧请求的方法是改为发出某些主题:
private reactionsTrigger$ = new Subject<void>();
public getReactions() {
this.reactionsTrigger$.next();
}
现在,我们有一个可观察到的代表触发新请求的事件流。现在,您可以将OnInit
实施为以下形式:
public ngOnInit() {
this.reactionsTrigger$.pipe(
// Use this line if you want to load reactions once initially
// Otherwise, just remove it
startWith(undefined),
// We switchMap the trigger stream to the request
// Due to how switchMap works, if a previous request is still
// running, it will be cancelled.
switchMap(() => this.http.get(…)),
// We have to remember to ensure that we'll unsubscribe from
// this when the component is destroyed
takeUntil(this.destroy$),
).subscribe(reactions => this.reactions = reactions);
}
// Just in case you're unfamiliar with it, this is how you create
// an observable for when the component is destroyed. This helps
// us to unsubscribe properly in the code above
private destroy$ = new Subject<void>();
public ngOnDestroy() {
this.destroy$.next();
this.destroy$.complete();
}
行
switchMap(() => this.http.get(…)),
在您的情况下,实际上可能会将事件切换到forkJoin
:
switchMap(() => forkJoin([rxnsObservable, headCountObservable])),
如果您希望单个事件流重新触发两个请求。
答案 1 :(得分:2)
看到一个显示HTTP请求实际 trigger 的代码段将很有帮助,但它很可能是一个UI组件,它可以在单击时调用一个函数。
使用RxJS 6解决此问题的方法是使用Subject
接收点击事件,然后使用switchMap
运算符取消未完成的请求以防止背压。这是一个示例:
private clickSubject$: Subject<void> = new Subject();
constructor() {
this.clickSubject$
.pipe(switchMap(() => forkJoin([rxnsObservable, headCountObservable])))
.subscribe((results) => // handling)
}
onClick() {
this.clickSubject$.next(undefined);
}
如果您要在多个地方执行http请求,请使用this.clickSubject$.next(undefined)
;
答案 2 :(得分:1)
您只需在RxJs中使用反跳运算符即可:
debounce(1000);
提供了一种在发送任何请求之前设置延迟(以毫秒为单位)的方法,
该示例仅用一个请求替换了1000ms内触发的所有请求。
更多详细信息:
fromEvent(input, 'input').pipe(
map((e: any) => e.target.value),
debounceTime(500),
distinctUntilChanged()
).subscribe(
(data) => {
this.onFilterTable({column: fieldName, data});
}
);